DRAGANECI DENISA

TIRTAU MIHAI - SORINGrupa 2205 BN=11

TEMA 1

1. pa=752 mmHg;

a).pm=(1,5n+0,5)bar=17 bar

pa=752 mmHg=752/750=1,0026bar

p=pa+pm=18,0026bar pm=17bar=17*105Pa

pa=1,0026*105Pa

p=18,0026*105Pa

pm=17*750=12750mmHg

pa=752mmHg

p=13502mmHgpm==17,329*104mmH2Opa==1,0224*104mmH2O

p=18,3514*104mmH2O

pm==17,329 kgf/cm2

pa==1,0224kgf/cm2

p=18,3514kgf/cm2b).pv=(755-4n)mmHg=711mmHg;pa=752mmHg;p=pa-pv

pv==0,948bar

pa=1,0026bar

p=0,0546bar

pv==0,948*105Pa

pa=1,0026*105Pap=0,0546*105Pa

p=41mmHg

pv =0,966*104mmH2O

pa==1,0224*104mmH2Op=0,0564*104mmH2O

pv==0,966kgf/cm2

pa==1,0224khf/cm2p=0,0564kgf/cm2

2.Dm=(100-2n)t/h=78t/h; p1=11bar; t1=(100+40ln11)C=195,9C=469,05K; p2=(50+3*11)bar=83bar;=1000kg/m3;c=4,18+0,002t kJ/kg*K

Fluid incompresibil=>v=cta).lt,12=v(p1-p2)p= m = Dm

v=

lt,12=Pa=-72*102J

p==156*103Wb).h1=cvt1=(4,18+0,002t)*469,05kJ/kgK

h2-h1=-lt,12

h1-h2h2=h1+(4,18+0,002t)*469,05+72*102 kJ/kg

=>T2= ==3539,19K

T=T2-T1=3539,19-469,05=3070,14K3.V=(0,4n)m3=4,4m3

pm=(1,5+n)bar=12,5bar=12,5*105Pa

t=(20+2n)C=42C=315,15K

t2=(700+10n) C=810C=1083,15K

pat=760mmHg=760/750*105=1,013*105Pa

p=pat+pm=1,013*105+12,5*105=13,513*105Paa).pentru H2:MH2=2 kg/kmol

pV=mRT=m*()*T =>m=kg n=

n= =>VN=n*VM=0,265kmol*22,413m3/kmol=5,93m3

tm=

CMp =CMp(600)+[CMp(700)-CMp(600)](tm-600)/(700-600)= = 29,33+(29,44-29,33)*(699,15-600)/100=29,43kJ/kmolKCMv=CMp-RM=29,43kJ/kmolK-8314,3*10-3kJ/kmolK=21,11kJ/kmolK

cv = =21,11/2=10,555kJ/kgKQ12=m*cv*(t2-t1)=4,53*10,555*(1083,15-315,15)=36721,26kJb).pentru CO2:

MCO2=44kg/kmol

CMp =47,32+(49,56-47,32)*(699,15-600)/100=49,54kJ/kmolKCMv =49,54kJ/kmolK 8,314kJ/kmolK=41,226kJ/kmolK

=

Q12=m*cv *(t2-t1)=4,53*0,936*768=3256,381kJ4.gaz perfect=0,001n kmoli=0,001*11=0,011kmoli

M=40kg/kmol

CMp=48kJ/kmolK

p1=1bar=105Pa

t1=27C=300,15K

a).transformare izocora:

T2=(2+0,05n)T1=765,382K

V-ct =>v1=v2p1V1=mRT1 => V1=mRMT1/Mp1=nMRMT1/Mp1=nRMT1/p1V1=0,011*8314,3*300,15/105=0,274m3V1=V2=0,274m3p1/T1=p2/T2 =>p2=p1T2/T1=105*765,382/300,15=2,549*105PaQ12=mcvT

n=m/M => m=n*M=0,011*40=0,44 kgcp-cv=R=RM/M => cv=cp-RM/M=1,2-8,314/40=0,992kJ/kgKcp=CMp/M=48/40=1,2kJ/kgK

Q12=0,44*0,992*(765,382-300,15)=203,064kJ

L12=0

U=Q12-L12=203,064kJ

H=Q12+V(p2-p1)=m*cp*(T2-T1)=0,44kg*1,2kJ/kgK*465,232K=245,642kJ

S=S2-S1=cv*ln(T2/T1)+R*ln(V2/V1)=0,992*0,936+8314,3*0=0,928kJ/Kb).transformare izobara: T2=(2+0,05n)T1=765,3825K

p=ct => p1=p2=105Pa

V1/T1=V2/T2 => V2= V1T2/T1=0,274*765,3825/300,15=0,6987m3Q12=mcp(T2-T1)=0,44*1,2*465,2325=245,642 kJL12=p1(V2-V1)=105*0,4247=0,4247*105JU=Q12-L12=245,642*103-0,4247*105=203172J=203,172 kJH=Q12=245,642 kJ

S=mcpln(T2/T1)-Rln(p2/p1)=0,44*1,2*0,936=0,494kJ/Kc) transformare izoterma: p2=(2+0,05n)p1=(2+0,05*11)*105=2,55*105Pa

T=ct => T1=T2=300,15K

p1/p2=V2/V1 =>V2=p1V1/p2=105*0,274/2,55*105=0,107m3

Q12=L12=p1V1ln(V2/V1)=105*0,274*(-0,94)=-25764,2kJQ12=L12=-25764,2kJ

U=Q12-L12=0

H=0

S=Q12/T=-25764/300,15=-85,837 kJ/K

d) transformare adiabatica: T2=(2+0,05n)T1=765,3825K

Q=0

p1V1k=p2V2kT1V1k-1=T2V2k-1 =>V2k-1=T1V1k-1/T2; V20,2=300,15*(0,274)0,2/765,3825=0,302m3k=cp/cv0=1,2/0,992=1,2

V2=0,0025m3p2=p1(V1/V2)k =>p2=105*(109,6)1,2=280,396*105PaQ12=0

U=mcvT=0,44*0,992*(765,3825-300,15)=203,064kJ

L12=-U=-203,064 kJ

H=mcpT=0,44*1,2*465,2325=245,642kJ

S=0e) transformare politropa: T2=(2+0,05n)T1=765,382K

p2=(2+0,05n)p1=(2+0,05*11)*105=2,55*105PaU=mcvT=0,44*0,992*(765,3825-300,15)=203,064kJ

H=mcpT=0,44*1,2*465,2325=245,642kJ

=>n=10

L12=(P1V1/n-1)(1-T2/T1)=(105*0,274/9)(1-765,382/300,15)=-4718,88kJQ12=(k-n)/(n-1)*L12=-4614,01kJ

S=cpln(T2/T1)-rln(p2/p1)=-193,45kJ/K

Transf.PresiuneVolumTemperaturaQ12L12U

HS

P1 (Pa)P2 (Pa)V1(m3)V2(m3)T1(K)T2(K)kJkJkJkJkJ

IzocoraV=ct

1052,549*1050,2740,274300,15765,382203,0640203,064245,6420,928

IzobaraP=ct1051050,2740,6987300,15765,382245,6420,4247* 105203,172245,6420,494

IzotermaT=ct1052,55* 1050,2740,107300,15300,15-25764,2-25764,200-85,837

AdiabataQ=0105280,396*1050,2740,0025300,15765,3820-203,064203,064245,6420

Politropa1052,55*1050,2740,249300,15765,382-4614,01-4718,88203,064245,642-193,45

5.

t=(200+n)C=211C=484,15Kp=(760-0,1*11)mmHg=758,9mmHg=758,9/750*105=1,011*105Pa

rCO2=(10+0,5*11)%=15,5%

rH2O=(50-0,2*11)%=47,8%

rN2=36,7%a) Mam=riMi=rCO2MCO2+rH2OMH2O+rN2MN2=

MCO2=44kg/kmol

MH2O=18kg/kmol

MN2=28kg/kmolcv=cp-R

Mam=RM/Ram => Ram=RM/Mam=8314,3/25,7=323,51J/kmol

cpam=gicpicp CO2=42/44=0,95 kJ/kgKcp H2O=36/18=2kJ/kgK

cp N2=30/28=1,07kJ/kgK

EMBED Equation.3

cpam=0,021*0,95+0,026*2+0,031*1,07=0,01995+0,052+0,03317=0,10512 kJ/kgKkam=0,10512*103/(0,10512*103-323,51)=105,12/(-218,39)=-0,48b) la stare normala: N=Mam/VM,N=323,51/22,414=14,433kg/m3 la starea la cos:

pV=mRT => p=mRT/V =>p=RT =>=p/RamT=1,011*105/323,51*484,15=0,645kg/m3_1289487675.unknown

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