1)analiza de regresieX=variabila independentaY=variabila dependenta

Y=0.3x+7.5 X Y X^210 10 10020 15 40030 15 90040 20 1600

SUME 100 60 3000n=5

construim model matematic liniar de o variabiladreapta y=ax+baflam coeficientii a si b rezolvand sistemul normal Gaussformat din 2 ecuatii liniare cu 2 necunoscute a si b

5025a+145b=2595 ECUATIA DREPTEI145a+5b=81 Y=0.3x+7.5

a= 0.3b= 7.5

2)analiza de corelatieConvarianta 37.5

Coef de corelatie 0.948683

R^2=0.94868

3)previzionare CARE ESTE Y PT X=6?CONFORM MODELULUI DETERMINATG(6)=0.3*6+7.5 9.3

9.30.3

intercept 7.5

5 10 15 20 25 30 35 40 450

5

10

15

20

25

f(x) = 0.0016666667x̂ 3 - 0.125x̂ 2 + 3.0833333333x - 10R² = 1

Y

5 10 15 20 25 30 35 40 450

5

10

15

20

25

f(x) = 0.0016666667x̂ 3 - 0.125x̂ 2 + 3.0833333333x - 10R² = 1

Y

Model liniar Model patraticX*Y Y calculat Y calculat

100 10.5300 13.5450 16.5800 19.5

1650

ECUATIA DREPTEIY=0.3x+7.5

5 10 15 20 25 30 35 40 450

5

10

15

20

25

f(x) = 0.3x + 7.5R² = 0.9

Y

5 10 15 20 25 30 35 40 450

5

10

15

20

25

f(x) = 0.0016666667x̂ 3 - 0.125x̂ 2 + 3.0833333333x - 10R² = 1

Y

5 10 15 20 25 30 35 40 450

5

10

15

20

25

f(x) = 0.0016666667x̂ 3 - 0.125x̂ 2 + 3.0833333333x - 10R² = 1

Y

5 10 15 20 25 30 35 40 450

5

10

15

20

25

f(x) = 0.3x + 7.5R² = 0.9

Y