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Calculul grinzii Arhitectura constructii

 

CALCULUL GRINZII

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l0m1 = lg1 - bstalp;

l0m2 = lg2 - bstalp;

l0m1 = 5,7 – 0.3-0.25 = 5,15 m;

l0m2 = 5.7 –0.3-0.25 = 5.15 m;

 

Calculul incarcarilor 

Nr.

crt.Denumirea inc 939i86j 59;rcare

Valori normate

daN/mn

Valori de calcul

daN/m

1. Greutate proprie

0,25 x 0,5 x 2500

312.5 1,1 343.75

2. Incarcare transmisa de placa

gp x l

2485.2 1,2 2982.24

3. Incarcari utile

gu x l

1282.5 1,4 1795.49

Total4080.2 5121.49

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q=5121.49 daN/m;

daN·m;

daN·m;

daN·m;

Q A = 0,45 ·q · l0m1 = 0,45 · 5121.49 · 5,1 5= 11753.82 daN;

QBdr  = Q A = ± 0,65 ·q · l0m1 = ± 0,65 ·5121.49 · 5,1 5= ± 16977.74 daN;

QC = 0,55 ·q · l0m2 = 0,55 · 5121.49 · 5,1 5= 14365.78 daN;

Stabilirea inaltimii necesare a grinzii ( hnec  );

p = 1 ;

;

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Se adopta hgr = 50 cm;

h0ef  = 50 – 2 –0,8 = 47,2 cm;

 

Dimensionarea armaturii 

l1 = 0,8 · l0m1 = 0,8 · 5,1 = 4,08 m;

l2 = 0,6 · l0m2 = 0,6 · 5,1 = 3.06m;

 

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;

 

Dimensionarea campului 1

;

;

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  cm2;

cm2;

 Armatura in camp

 Aa1  = 8.63 cm2;

Se adopta 5ф16/m

Se adopta aria de armatura Aaef   = 10,05 cm2;

Dimensionarea reazemului B

;

  cm2;

cm2/m;

 Armatura in camp

cm2;

Se adopta 5ф16/m

Se adopta aria de armatura Aaef   = 10,05 cm2;

Dimensionarea campului 2

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;

 

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;

 cm2;

cm2/m;

 Armatura in camp

 Aa1  = 9.82 cm2;

Se adopta 5ф16/m

Se adopta aria de armatura Aaef   = 10.05 cm2;

Dimensionarea armaturii in reazamul A

M A = 0,6 ·Mmax = 0,6 · 1211000 = 7266000 daN·m

;

  cm2;

cm2;

 Armatura in camp

cm2;

Se adopta 3ф16/m

Se adopta aria de armatura Aaef   = 6.03 cm2;

 Calculul la starea limita de rezistenta in sectiuni

  inclinate

Qmax=16977.74daN

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0.5

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