un amestec de metan si etan are un continut procentual in carbon de 78
TRANSCRIPT
Un amestec de metan si etan are un continut procentual in carbon de 78.75%Calculeaza compozitia procentuala volumetrica si compozitia procentuala de masa a amestecului.
a)
x - masa de metany = masa de etan
x + y = 100 (1)
16 g CH4 .......12 g C x g CH4 ......... x' g Cx' = 12x/16 = 3x/4
30 g C2H6 ....24 g C y ...............y' g CY' = 24y/30 = 4y/5
3x/4 + 4y/5 = 78.75 (2)
din ecuatia 1 si 2 am calculat x =25% CH4
y = 75% C2H6
b) Se determina volumul din fiecare considerand ca sunt 25g CH4 si 75g C2H6
16 g CH4.....................22,4 L25 g CH4.......................xx=25∙22,4/16 = 35 L CH4
30 g C2H6....................22,4L75g C2H6.........................yy=75∙22,4/30 = 56 L C2H6
V total = 35 + 56 = 91L91 L amestec...............35 L CH4...............56 L C2H6
100 L amestec..............x............................yx=38,46 % CH4
y=61,54% C2H6