diagrama fe3c - probleme
TRANSCRIPT
Calculati cantitatea de faze si constituenti din aliajul Fe-C dat:
Def.: cantitatea procentuala a uneia dintre faze se obtine raportand segmentul opus (in raport cu compozitia fazei respective) la suma segmentelor.
OTELURI0.002 – 0.77 %C – otel hipoeutectoid ⇒ A ∈ (0.002 – 0.77) – Fα + Ce + P0.77 %C – otel eutectoid0.77 – 2.11 %C – otel hipereutectoid ⇒ B ∈ (0.77 – 2.11) – P + CeFONTE2.11 – 4.3 %C – fonta hipoeutectica ⇒ C ∈ (2.11 – 4.3) – P + Ce + Le4.3 %C – fonta eutectica4.3 – 6.67 %C – fonta hiperutectica ⇒ D ∈ (4.3 – 6.67) – Le + Ce
1. Otel hipoeutectoidA ∈ (0.002 – 0.77) – Fα + Ce + P
Q Fα = 6.67−A
6.67−0.002 · 100%
QCe = A−0.002
6.67−0.002 · 100%
QP = A−0.002
0.77−0.002 · 100%
2. Otel hipereutectoidB ∈ (0.77 – 2.11) – P + Ce
QP = 6.67−B
6 .6 7−0.77 · 100%
QCe = B−0.77
6.67−0.77 · 100%
3. Fonta hipoeutecticaC ∈ (2.11 – 4.3) – P + Ce + Le
QA = 4.3−C
4.3 –2 .11 · 100%
100 % A ………………….21% CeQA ………………………… X = QCe
QP = 4.3−C
4.3−0.77 · 100%
QLe = C−0. 77
4.3−0.77 · 100%
4. Fonta hiperutecticaD ∈ (4.3 – 6.67) – Le + Ce
QCe = D – 4.3
6.67−4.3 · 100%
QLe = 6.67−D
6.67−4.3 · 100%