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PROIECT LA CONSTRUCTII METALICE

Proiect la constructii metalice

Moldovan Teodor-Dan

ICG II

FERMA METALICA

Cuprins

1.Schema geometrica2.Calculul incarcarilor 2.1 Din zapada 2.1.1.Calaculul invelitorii

2.1.1.Calaculul panei

2.1.1.Calaculul fermei 2.2.Calculul invelitorii

2.3.Calculul panelor

3.Calculul static4.Calcul static Axis5.Dimensionare 5.1.Alegerea alcatuirii sectiunii barelor 5.2.Bara intinse 5.3 Bare comprimate

6.Calculul sudurii8.Extras9.DesenPROIECT LA CONSTRUCTII METALICE

1.Schema geometrica

hm=

hr=

L=23 m

Alegem: hr=1,5m; hm=2,7m; =>Dh=hm - hr=2,7 - 1,5=1,2; =2,875;

=0,521 => a1=27,51 ;2.Calculul incarcarilor

2.1 Din zapada (cf. STAS 10101/21-92)

Sibiul se afla in zona B, pentru care greutatea de referinta a zapezii gz=1,2 kN/m2 (perioada de revenire- 10 ani)

coeficient ce se considera pentru conditii normale de expunere si are valoarea ce=0,8

czi, coeficientul de aglomerare cu zapada, pentru o structura cu acoperis in 2 pante pentru a=5.95 (corespunzator unei inclinatii de 10 %) => czi=1

=1 x 0,8 x 1,2=0,96 kN/m2 (96 daN/m2)Coeficientul incarcarii n, pentru zapada este notat de STAS 10101/21-92 cu si are expresiile:

pentru stari limita de rezistenta si

stabilitate

pentru stari limita ale exploatarii normale

(sageti)

Din STAS 10101/21-92 rezulta: =2,2; =1,4

gp= incarcari gravitationale, altele decat din zapada

Ele se aproximeaza la inceput si dupa alegerea sectiuniilor se verifica daca a fost apreciata corect.Ele provin din:

greutatea invelitorii

greutatea panelor

greutatea fermelor, si se stabilesc in functie de situatia reala pentru calculul invelitorii, panelor si fermei.greutatea invelitoriipresupusa din ONDATERM 101/60:~13,9kg/m2greutate panelorpresupunand ca sunt din profile laminate la cald (I, U, IPE) cu h=~140 mm => ~14 kg/mlPentru distanta dintre pane =2,875 m =>greutatea panelor pe m2 de hala =~5 kg/m2Pentru ferma, la o deschidere de 23 m, travee de 6,8 m si incaracare totala 150 kg/m2 => ~11 kg/ m2 2.1.1.Pentru calaculul invelitorii rezulta:

=2,136 0,66

=1,369 0,42

2.1.2.Pentru calaculul panei rezulta:

=2,192 0,66

=1,396 0,42

2.1.3.Pentru calaculul fermei rezulta:

=2,187 0,66

=1,393 0,42

Incarcarile aferente de calcul (pt. rezistenta si stabilitate) sunt:

2.1.1.Pentru invelitoare:

=>2,136 x 96=205,056 daN/m2 pt. rezistenta

=>1,369 x 96=131,42 daN/m2 pt. sageata

2.1.2.Pentru pana:

=>2,192 x 96=210,43 daN/m2 pt. rezistenta

=>1,396 x 96=134,016 daN/m2 pt. sageata

2.1.3.Pentru ferma:

=>2,187 x 96=209,95 daN/m2 pt. rezistenta

=>1,393 x 96=133,728 daN/m2 pt. sageata

2.2. Calculul invelitorii Se alege invelitoare de tip ONDATERM 101/60 cu greutatea de 13,9 kg/m2.In afara de greutatea proprie invelitoarea mai trebuie sa preia si efectul greutatii din zapada si al presiunii vantului.Presiunea vantului actioneaza in sens contrar efectului greutatii asa ca ele nu se insumeaza. Ca urmare calculul se face la efectul greutatii proprii si a zapezii, care actioneaza in acelasi sens.

a=5.95 => cosa=0,9946

=> sina=0,1036

q=pz + gp=225 + 15,38= 220,38 daN/m2Din tabelul ONDATERM se observa ca panoul 101/60 poate fi folosit pana la deschideri 3,00 m (simpla rezemare) respectiv 3,50 m (rezemare continuua).

2.3. Calculul panelor

Panele de streasina si coama, desi mai putin solicitate datorita incarcarii numai de pe panouri l, se realizeaza din aceleasi profile ca si panele curente.

=>S=~649,21 daN/ml

gx=g x cosa=649,21 x 0,9946=~645,70 daN/m

gy=g x sina=649,21 x 0,09946=~67,25 daN/m

lpana=T=6,8 m

A.Pana simplu rezemata

3732 daNm=373200 daNcm

388,705 daNm=38871 daNcm

EMBED Equation.3 =>corespund profilele:

I20: Wx=214 cm3 Wy= 26 cm3 (G=26,3kg/m)

U20: Wx=191 cm3 Wy= 27 cm3 (G=25,3 kg/m)

=>Se observa ca rezulta sectiuni cu greutati de ~26 kg/m care corespund unui consum de otel de ~26/2,875=9,04 kg/m2 ceea ce este prea mult.

B.Pana continu rezemata

Panoul marginal:

Mxm=0,095 x q x lx2=0,095 x 645,70 x 6,82=2836,43 daNm=283643 daNcm

Mxi=0,0625 x q x lx2=0,0625 x 645,70 x 6,82=1866,07 daNm=186607 daNcm

388,60 daNm=38860 daNcm

Dimensionarea in panourile intermediare:

EMBED Equation.3 =>corespund profilele:

I18: Wx=161 cm3; Wy=19,8 S=338,1 daN/m

Panoul marginal

Din calculele anterioare se observa ca hotaratoare pentru dimensionare este conditia de rezistenta Mxm fiind cu aproximativ 1000 daN/m >Mxi.Cum My ramane neschimbat in panoul marginal insemna ca pana trebuie intarita fata de axa maxima de inertie (x-x).

EMBED Equation.3

1245,59+490,76=1736daN/cm2U13=0 (SM)7=0

189,44x2,875-23,68x2,875+O38x1,79=0=> O38=-266,2 kN

=>x=2,875 x =0,2996

=>h=1,5+0,2996=1,8 m => ho=cosax 1,8=1,79 m

(SM)A=0

23,68x14,39-189,44x14,39+D37x7,98=0=>D37=298,6 kN

=>d=14,39 m

27,5571

hd=7,98 m

4.VERIFICARE AXISBaraN [kN]Lungime (m)

D 3-7298,623,243

U 7-4389,035,750

D 4-645,163,560

D 2-430,273,944

U 4-11403,445,750

U 1-702,875

M 1-3-189,441,5

O 3-8-266,192,891

M 7-8-47,361,80

D 7-6-155,893,56

O 8-6-266,192,891

O 6-5-427,812,891

M 4-5-47,362,40

O 5-2-427,442,891

5.Dimensionare

5.1.Alegerea alcatuirii sectiunii barelor:

Bare intinse

Bare comprimate

grosime guseu: tg=10 mm

5.2.Bara intinse

Dimensionare de rezistenta:

In functie de aceasta valoare se alege din tabelul cu profile o sectiune cu .

Verificarea de rezistenta:

Verificare de zveltete:

U37=298,62 kN=29862daNl=3,243m

Alegem corniera: 65x50x7 cu Aef=15,2cm2

Verificari:

de rezistenta:

de zveltete:

x-x:

y-y:

U74=389,03 kN=38903daNl=5,75m

Alegem corniera: 80x60x7 cu Aef=18,76cm2

Verificari:

de rezistenta:

de zveltete:

x-x:

y-y:

U46=45,16 kN=4516daN l=3,56m

Alegem corniera: 40x20x4 cu Aef=4,52

Verificari:

de rezistenta:

de zveltete:

x-x: fals

y-y:

=> alegem alta corniera 60x40x6 cu Aef=11,36

de zveltete:

x-x:

y-y:

D24=280,32 kN=28032daNl=3,94m

Alegem corniera: 60x40x6 cu Aef=11,36cm2

Verificari:

de rezistenta:

de zveltete:

x-x:

y-y:

U4-11=403,44 kN=40344daNl=5,750m

Alegem corniera: 80x65x8 cu Aef=22cm2

Verificari:

de rezistenta:

de zveltete:

x-x:

y-y:

D17=0 kN=0daN l=2,875m

Alegem corniera: 60x30x5 cu Aef=8,58cm2

Verificari:

de rezistenta:

de zveltete:

x-x:

y-y:

5.3 Bare comprimate

In functie de tipul sectiunii alese (L-cu aripi egale sau L-cu aripi inegale) se scot din tabel coeficientii kx si ky cu care se calculeaza:

;

cu care se intra in tabelul (R=24->OL37) si se determina un si un in functie de care se scot din tabelele coeficientilor de flambaj (curba C pentru axa x-x si curba B pentru axa y-y) coeficientii si .Cu cea mai mica din cele 2 valori se determina:si se alege grupa de corniere care are aria si ix respectiv iy proprii.

Cu aceste ultime valori se calculeaza si[care trebuie sa fie =83 =>=0,6

ky=2,00

=>

=>=63 =>=0,810

------------------------------------------------------------------------

=>70x70x6

Abr=16,26cm2

ix=2,13

iy=3,23

O38=-266,19 kN=-26619 daN l=2,891m

kx=4,60

=>

=>=114 =>=0,424

ky=2,00

=>

=>=90 =>=0,622------------------------------------------------------------------------

=>90x90x9

Abr=31cm2

ix=2,74

iy=4,09

M78=-47,36 kN=-4736 daN l=1,8m

kx=4,60

=>

=>=143 =>=0,308

ky=2,00

=>

=>=101 =>=0,546

------------------------------------------------------------------------

=>50x50x4

Abr=7,78cm2

ix=1,52

iy=2,39

D76=-153,89 kN=-15389 daN l=3,56m

kx=4,60

=>

=>=151 =>=0,284

ky=2,00

=>

=>=106 =>=0,513

------------------------------------------------------------------------

=90x90x8

Abr=27,8cm2

ix=2,74

iy=4,06

O86=-266,19 kN=-26619 daN l=2,891m

kx=4,60

=>

=>=114 =>=0,424

ky=2,00

=>

=>=90 =>=0,622------------------------------------------------------------------------

=>90x90x9

Abr=31cm2

ix=2,74

iy=4,09

O65=-427,81 kN=-42781 daN l=2,891m

kx=4,60

=>

=>=98=>=0,508

ky=2,00

=>

=>=77 =>=0,715

------------------------------------------------------------------------

=>100x100x12

Abr=45,4cm2

ix=3,02

iy=4,55

M45=-47,36 kN=-4736 daN l=2,4m

kx=4,60

=>

=>=168=>=0,239

ky=2,00

=>

=>=119 =>=0,437

------------------------------------------------------------------------

=>60x60x5

Abr=11,64cm2

ix=1,82

iy=2,81

O52=-427,81 kN=-42781 daN l=2,891m

kx=4,60

=>

=>=98=>=0,508

ky=2,00

=>

=>=77 =>=0,715

------------------------------------------------------------------------

=>100x100x12

Abr=45,4cm2

ix=3,02

iy=4,55

EMBED Equation.3 6.Calculul sudurii

Vom calcula grosimea si lungimea necesara a cordonului de sudura pentru ca acesta sa poata transmite si sa preia fortele axiale.

6.1 Imbinarea talpii inferioare

l=100mm

7.Solidarizari

Bare intinse: l80 x i1

Bare comprimate: l40 x i1

EMBED \* MERGEFORMAT

EMBED \* MERGEFORMAT

EMBED \* MERGEFORMAT

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