2015 chimie judeteana clasa a xia subiectebarem
Post on 07-Jul-2018
217 Views
Preview:
TRANSCRIPT
8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem
httpslidepdfcomreaderfull2015-chimie-judeteana-clasa-a-xia-subiectebarem 17
CCl
PdPb2+
OL
Subiectul I helliphelliphelliphelliphelliphelliphelliphelliphellip
A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
Se dau formulele de structură pentru
I Linalool din ulei delavandă
IV Amfetamina
a Precizaţi denumirea conform IUPb Scrieţi formulele structurale ale stc Substanţele IV şi V sunt insolubinumai icircn unul din cazuri se păstdeosebirea dintre aceste substanţe
B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
1 Scrieţi formulele de structură pen
a transndash3ndashhexenă + Br2
b cisndash2ndashbutenă + [O] + H2O
c transndash2 3ndashdimetilndash3ndashhexen
d 2ndashbutină + H2
Oe ciclopentenă + C6H5ndashC
Ondash 2 Degradarea Hofmann a bazelorecuaţiile reacţiilor chimice de obţin
Str General B
DIR
IcircNVĂȚĂM
KMnO4 HO oline
Ni
Clasa a XI-a
MPIADA DE CHIMIE ndash etapa jude ţ eană
21 februarie 2015
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
compuşii
II Citral din uleide lămacircie
III
Benzedrina) V
AC pentru I II III şi IVereoizomerilor corespunzători compuşilor II şi II
le icircn apă dar solubile icircn soluţie de HCl 5 Duează solubilitatea icircn soluţie de HCl 5 Ex
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
ru stereoizomerii produşilor următoarelor reacţii
ă + H2
OndashH
cuaternare de amoniu are loc la temperaturire a etenei prin degradări Hofmann ale metilndashetil
erthelot nr 28-30 Sector 1 010168 Bucureşti
Tel +40 (0)21 40 63 00
wwweduro
ECȚIAGENERALĂ
NT PREUNIVERSITAR
helliphelliphelliphelliphelliphelliphellip 20 puncte
helliphelliphelliphelliphelliphelliphelliphellip 12 puncte
Efedrina din plantade cacircrcel
Tetracaina
Iă reacţia cu anhidrida aceticălicaţi atacirct asemănarea cacirct şi
helliphelliphelliphelliphelliphelliphelliphellip 8 puncte
ai mari de 100degC Modelaţindashbutilndashaminei
8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem
httpslidepdfcomreaderfull2015-chimie-judeteana-clasa-a-xia-subiectebarem 27
ndash H2O230degC
+ 2HA
+ (CH3)
ndash CH3O
Subiectul II helliphelliphelliphelliphelliphelliphelliphelliphellip
A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip1 bdquoParabeniirdquo sunt compuşi ordezinfectanţi şi arome icircn industria
următoarei schemeC6H5ndashOH + KOH A
2 B C + C6H5ndashOH + CO2
C acid pndashhidroxibenzoic
Se cerea Scrieţi ecuaţiile reacţiilor reprezeb Denumiţi conform IUPAC substac Pentru cei doi acizi izomeri din159degC precum și constantele de acid Icircn Australia se interzice folosireainterdicție2 a Scrieți formulele structuralepndashmetoxifenoxid
b Acidul pndashhidroxibenzoic estNaHCO3
HOndashC6
oline OndashC
Ordonați cele patru specii acide icircn oB helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellipUn amestec de acid oxalic și acid foun amestec gazos cu volumul de 06Se cerea Calculați raportul molar al celor db O probă H2C2O4middot2H2O cu masaacidului cristalizat (impuritățile nu r
Subiectul III helliphelliphelliphelliphelliphelliphelliphellip
A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
1 Etanolaminele sunt substanțe foletilenoxid Se introduc icircn soluție apcu o cantitate dublă de etilenoxid gsepară 915 kg monoetanolamina 6Să se calculezea Compoziția icircn procente molare ab Randamentul de transformare a a2 Scrieți ecuațiile reacțiilor posibilde reacție
B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellipIcircntr-un vas cu dop rodat se cacircntăre
brom 005M Se icircnchide vasul și seprin reacția cu excesul de brom colamidon pacircnă la decolorare Calculcondițiile date tiosulfatul de sodiu s
p =
ndash 2KA
Str General B
DIR
IcircNVĂȚĂM
CO2 H2SO4
ndashKHSO4
ROH(H2SO4)
ndashH2O
OSO3
O3H
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellipanici derivaţi de la acidul parahidroxibenzoifarmaceutică cosmetică şi alimentară Aceste s
B acid salicilic
parabeni
E (aromă de anason)
tate icircn schemănţa (E) şi parabenii conservanţi preparaţi cu CH
schemă atribuiți valorile potrivite ale puncteloitate Ka = 105middot10-4 și Ka = 2610-5 Justificați al
parabenilor icircn scopurile enumerate icircn text Form
ale următorilor anioni icircn ordinea creșterii bazi
un acid diprotic pentru care se dau ecuațiile
H4ndashCOOH + HCO3 oline HOndashC6H4ndashCOO oline + H2CH4ndashCOO oline + HCO3 oline HOndashC6H4ndashCOO oline + CO3
2
rdinea descrescătoare a acidității lorhelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
rmic obținut din greșeală se tratează cu 10 g sol72 L (cn) și cu densitatea de 1464 gL (cn)
oi acizi icircn amestece 0130 g este titrată cu 20 mL soluție de KM
eacționează cu KMnO4)
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
site icircn cosmetică industria textilă și de pielărieasă 246 m3 amoniac la temperatura de 27degC șiazos Se obține un amestec al celor trei etanola0 kg dietanolamina și 298 kg trietanolamina
mestecului final de aminoalcoolioniacului și conversia icircn dietanolamină icircntre monoetanolamină (colina) și acid acetic
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellipsc 002 g fenol brut Se adaugă 10 mL acid ac
lasă la icircntuneric 20 minute apoi se adaugă 10orează soluția icircn brun şi se titrează cu soluție daţi puritatea probei de fenol dacă s-au consutransformă icircn Na2S4O6
atm 125degC
erthelot nr 28-30 Sector 1 010168 Bucureşti
Tel +40 (0)21 40 63 00
wwweduro
ECȚIAGENERALĂ
NT PREUNIVERSITAR
helliphelliphelliphelliphelliphelliphelliphellip 25 puncte
helliphelliphelliphelliphelliphelliphelliphellip 15 punctec utilizaţi drept conservanţibstanţe se pot obţine conform
ndash OH respectiv C7H15 ndash OHde topire 213degC și respectiv
egerealați o motivație pentru această
cității fenoxid pndashnitrofenoxid
reacțiilor icircn soluție apoasă de
3 oline
helliphelliphelliphelliphelliphelliphelliphellip 10 puncteuție de H2SO4 95 și se obține
O4 002M Calculați puritatea
helliphelliphelliphelliphelliphelliphellip 25 puncte
helliphelliphelliphelliphelliphelliphelliphellip 10 puncte
care se prepară din amoniac șipresiunea de 10 atm icircmpreună ine din care după distilare se
precizacircnd tipul fiecărui produs
helliphelliphelliphelliphelliphelliphelliphellip 8 punctetic glacial și 25mL soluție de
L soluție KI 1M Iodul formatNa2S2O3 01M icircn prezență deat 13 mL soluție Na2S2O3 Icircn
8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem
httpslidepdfcomreaderfull2015-chimie-judeteana-clasa-a-xia-subiectebarem 37
CH3MgBr (exces) H2O
HO ndash
K2Cr2O7 H+
HCl
C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
Se consideră produsul carbonilicpropionică (A) și acetona (B)
Se cerea Să se indice o schemă de reacțisimultan ambele substanțe (A) și (Bb Să se indice o schemă de reacțiiuna icircn alta
Subiectul IV helliphelliphelliphelliphelliphelliphelliphellip
A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
Substanța (A) are formula moleculcristalizat cu 24 dinitrofenilhidrazide la substanţa (A) se pot scrie ecua
A B D E + NaCl
acetonă + butanal F
F E + H2O
Compusul (B) are formula molec(DNFH) Compusul (E) colorează icirca Scrieți ecuațiile reacțiilor din schb Denumiți conform IUPAC substa
c La dozarea unei soluții a substandin proba de analizat
B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
La echilibrul unei reacţii chimiceCH3COOH 13 moli C2H5OH 23respectivă este 4 Să se calculezeechilibru se mai adaugă 1 mol C2H5
C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
Prin tratarea unui polialcool saturatreprezintă 13695 comparativ cu p
Se cerea Formula moleculară şi structurală b Scrierea ecuaţiilor reacţiilor chiraport cu aerul este 145c Volumul hidrocarburii măsurat lglobal al reacţiilor este 80
Se dau- Mase atomice H - 1 C - 12 N -- Volumul molar V = 224 Lmol- Masa moleculară a aerului microaer =- Constanta universală a gazelor
NOTĂ Timp de lucru 3 ore
Subiecte propuse de Ignat Iuliana
Str General B
DIR
IcircNVĂȚĂM
K2Cr2O7 H+ I2 NaOH
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
u formula moleculară C3H6O sub forma celo
i și condițiile acestora prin care pornind de la
și condițiile lor prin care cele două substanțe (A
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
ră C6H10O2 este neutră față de indicatorii acido a (DNFH) reacționează cu reactiv Tollens și d
iile reacțiilor chimice conform schemei de mai j
C D + CHI3
+ Frsquo
lară C8H18O2 reacționează rapid cu reactivroșu soluția de metilorange și reacționează rapi
mă și cele ale substanței (A) cu DNFH și (A) cunțele notate cu (A) (B) (C) şi (E)
ei (B) se consumă 15mL soluție K2Cr2O7 02M
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
icircntre etanol şi acid acetic compoziţia amestecmoli CH3COOC2H5 şi 23 moli H2O Constan
conversia totală de transformare a acidului acH la volum constant
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
cu anhidridă acidă icircn exces masa moleculară olialcoolul
a polialcooluluiice de obţinere a polialcoolului pornind de la hi
a 1 atm şi 27degC necesar obţinerii a 920 kg po
14 O - 16 Na - 23 S - 32 Cl - 355 K - 39 Cr
2896 gmol= 0082 atmmiddotdm3 molmiddotK
rofesor la Liceul Pedagogic bdquoDP Perpessicius
erthelot nr 28-30 Sector 1 010168 Bucureşti
Tel +40 (0)21 40 63 00
wwweduro
ECȚIAGENERALĂ
NT PREUNIVERSITAR
helliphelliphelliphelliphelliphelliphelliphellip 7 puncte
r doi izomeri ai săi aldehida
un compus unic să se obțină
) și (B) să se poată transforma
helliphelliphelliphelliphelliphelliphellip 30 puncte
helliphelliphelliphelliphelliphelliphelliphellip 15 puncte
- bazici formează un compusreacția iodoformului Pornind
os
ucas dar nu reacționează cucu reactiv Lucas
reactiv Tollens
Calculați masa substanței (B)
helliphelliphelliphelliphelliphelliphelliphellip 5 puncte
lui este următoarea 13 molita de echilibru la temperaturaetic dacă peste amestecul de
helliphelliphelliphelliphelliphelliphelliphellip 10 puncte
reşte cu 126 Această creştere
drocarbura a cărei densitate icircn
lialcool ştiind că randamentul
- 52 Mn - 55 Br - 80 I - 127
Br ăila
8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem
httpslidepdfcomreaderfull2015-chimie-judeteana-clasa-a-xia-subiectebarem 47
ndash H2O
230degC
+ 2HA
+ndash
C
O-
COO-K+
O-K+
OL
BA
Subiectul I helliphelliphelliphelliphelliphelliphelliphelliphellipA helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellipa 4 denumiri conform IUPAC times 1p
b Compusul II prezintă doi diastere
Compusul III prezintă 2 atomi de
2 perechi de
c Explicaţie helliphelliphelliphelliphelliphelliphelliphelliphellip
Asemănarea ndash caracterul ba
Deosebirea ndash Amfetamina (
HCl 5 Tetracaina după acilare
rămacircne solubilă icircn soluţia de HCl 5
B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip1 helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
a mezondash3 4ndashdibromhexan (mezofo
b cisndash2 3ndashbutandiol (mezoformă)
c (plusmn)ndash2 3ndashdimetilhexan (amestec r
d cisndash2ndashbutenă
e (plusmn)transndash1 2ndashciclopentandiol (a
2 Modelarea ecuaţiilor reacţiilor ch
se ca produşi finali de reacţie CH2=
Subiectul II helliphelliphelliphelliphelliphelliphelliphelliphellip
A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
1 a helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
C6H5ndashOH + KOH C6H5ndashO
2
acid pndashhidroxindash 2KA
OH
COO-K+
Str General B
DIR
IcircNVĂȚĂM
+ CO2 H2SO4
ndashKHSO
ROH(H2SO4)
ndashH2O
(CH3)2OSO3 CH3OSO3H
OHO-K+
+
COOR
OH
COOH
OCH3
MPIADA DE CHIMIE ndash etapa jude ţ eană
21 februarie 2015
EM DE EVALUARE ndash CLASA A XI-A
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
oizomeri Z (cis) E (trans) 2 structuri times 1p helliphellip
carbon asimetrici
nantiomeri (eritro plusmn treo plusmn) 4 structuri times 05p
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
zic demonstrat prin scrierea ecuaţiilor reacţiilor c
Benzedrina) după acilare pierde caracterul bazi
avacircnd icircn structura sa grefată şi o grupare amin
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
rmă)
cemic)
estec racemic)
imice degradări Hofmann (metilare urmată de icircn
CH2 şi (CH3)3N helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
oline K+
+ + CO2
benzoic
p = 6 atm 125degC
OH
COO-K+
erthelot nr 28-30 Sector 1 010168 Bucureşti
Tel +40 (0)21 40 63 00
wwweduro
ECȚIAGENERALĂ
NT PREUNIVERSITAR
4
helliphelliphelliphelliphelliphelliphellip 20 punctehelliphelliphelliphelliphelliphelliphelliphellip 12 punctehelliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p
himice
şi este insolubilă icircn soluţia de
o terţiară care nu se acilează
helliphelliphelliphelliphelliphelliphelliphellip 8 punctehelliphelliphelliphelliphelliphelliphelliphelliphelliphellip 5 p
călzire cu Ag(OH)) obţinacircndu-
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 3 p
helliphelliphelliphelliphelliphelliphelliphellip 25 puncte
helliphelliphelliphelliphelliphelliphelliphellip 15 puncte
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 7 p
OH
COOH
8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem
httpslidepdfcomreaderfull2015-chimie-judeteana-clasa-a-xia-subiectebarem 57
OH
COOH
COOH
OH
NO2
O-O-
b (E) acid pndashmetoxibenzoic helliphellip
parahidroxibenzoat de metil helliphelliphellip
parahidroxibenzoat de nndashheptil hellip
c
punct d
punct de to
Ka
Justificare
d Parabenii au potenţial efect cance
2 a helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
lt
b HOndashC6H4ndashCOOH gt H2CO3 gt HC
B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellipa HCOOH rarr CO + H2O hellip
H2C2O4 rarr CO + CO2 + H2
νamestgaze = 003 moli mgaze
b 5 H2C2O4 + 2 KMnO4 + 3 H2SO4
νKMnO4 = 00004 moli m H2C
Subiectul III helliphelliphelliphelliphelliphelliphelliphellip
A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip1 a 3 ecuaţii chimice times 1p helliphelliphellip
Compoziţia icircn procente molare a a
1579 (monoetanolamina)
b η = 95 c= 60 helliphelliphelliphelliphelliphellip
2 4 ecuaţii chimice times 1p helliphelliphelliphellip
B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
C6H5ndashOH + 3Br2 rarr C6H2Br3ndashOH +
Br2 + 2KI rarr 2KBr + I2 helliphelliphelliphellip
I2 + 2Na2S2O3 rarr Na2S4O6 + 2NaI
νNa2S2O3 = 13middot10
-4
moli helliphelliphelliphelliphellip νI2 = νBr2(exces) = 65middot10-4
moli helliphellip
νBr2 icircn reacţia cu fenolul = 6middot10-4
moli helliphellip
p = 94 helliphelliphelliphelliphelliphelliphelliphelliphelliphellip
Str General B
DIR
IcircNVĂȚĂM
O-
CH3O
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
e topire = 159degC
a = 105middot10-4
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
ire = 213degC
26middot10-4
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
rigen datorită nucleului benzenic helliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
lt
O3macr gt HOndashC6H4ndashCOO
macr helliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
09838 g νHCOOH νH2C2O4 = 43 helliphelliphelliphelliphellip
rarr 10 CO2 + K2SO4 + 2MnSO4 + 8 H2Ohelliphelliphellip
2O4middot2H2O = 0126 g p = 96923 helliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
estecului final 6316 (dietanolamina) 2105 (trietanolami
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
3 HBr helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
erthelot nr 28-30 Sector 1 010168 Bucureşti
Tel +40 (0)21 40 63 00
wwweduro
ECȚIAGENERALĂ
NT PREUNIVERSITAR
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphellip 05 p
helliphelliphelliphelliphelliphelliphelliphelliphellip 05 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p helliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphellip 10 punctehelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p
helliphelliphelliphelliphelliphelliphellip 25 puncte
helliphelliphelliphelliphelliphelliphelliphellip 10 punctehelliphelliphelliphelliphelliphelliphelliphelliphelliphellip 3 p
a) helliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p
helliphelliphelliphelliphelliphelliphelliphellip 8 puncte
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 phelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem
httpslidepdfcomreaderfull2015-chimie-judeteana-clasa-a-xia-subiectebarem 67
CH3
CH2
CH
OH
CHCCH3
CH3
OH
CH3
C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
a Modelarea ecuaţiilor reacţiilor
ozonizare urmată de hidroliză helliphellip
b Ararr helliprarr B helliphelliphelliphelliphellip
Brarr helliprarr A helliphelliphelliphelliphellip
Subiectul IV helliphelliphelliphelliphelliphelliphelliphellip
A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
a 8 ecuaţii chimice times 1p helliphelliphelliphellip
(A) (
(E)
b 4 denumiri conform IUPAC times 1p
(A) 2ndashetilndash3ndashoxondashbutanal
(B) 3ndashetilndash2 metilndash2 4ndashpentandiol
(C) 3ndashetilndash4 metilndash4ndashhidroxindash2ndashpe
(E) acid 2ndashetilndash3ndashmetilndash3ndashhidroxib
c
3 + K
νK2Cr2O7 = 0003 moli νB= 0009 mo
B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
Ctotal = 1
3
∙100
Ctotal = 8447 helliphelliphelliphelliphelliphelliphelliphellip
CH3 C CH
O
CHO
CH2
CH3
OH
CCH3
CH
C
O
CH3
CH2OH
CHCCH3
CH3
OH CH3
CH3 C CH CH2 C
CH3
Str General B
DIR
IcircNVĂȚĂM
C
CH3
CH3 C CH
OH CH2
CH3
O
C
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
himice şi condițiile acestora Se poate porni
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphellip
(A)
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
B) (C)
(F)
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
tanonă
utanoic
2Cr2O7 + 4H2SO4 3
hellip
l mB = 1314 g helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
CH3
CH2
CHCH
OH
CH3 CH
CH3
CH3 C CH
OH CH2
CH3
O
C
C
CH3
CH2OH
CHC
CH3
O
H CH2CH3 CH2
3 CH2CH3
erthelot nr 28-30 Sector 1 010168 Bucureşti
Tel +40 (0)21 40 63 00
wwweduro
ECȚIAGENERALĂ
NT PREUNIVERSITAR
O
CH3CCH3
H3
helliphelliphelliphelliphelliphelliphelliphellip 7 puncte
de la 2ndashmetilndash2ndashpentenă prin
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 3 p
(B)
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
helliphelliphelliphelliphelliphelliphellip 30 puncte
helliphelliphelliphelliphelliphelliphelliphellip 15 puncte
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 8 p
(D)
(Frsquo)
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p
+ K2SO4 + Cr2(SO4)3 + 7 H2O
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
helliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphellip 5 puncte
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 5 p
C
CH3
CH2OH
CHCCH3
CH3 O
O-Na+
O
H
C CH2
OH CH3
C
+ CHO
8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem
httpslidepdfcomreaderfull2015-chimie-judeteana-clasa-a-xia-subiectebarem 77
C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
a Formula moleculară C3H8O3 For
b Modelarea ecuaţiilor reacţiilor ch
c VC3H6(1 atm 27degC) = 30769 m3 helliphellip
NOTĂ Orice altă variantă corect
Barem elaborat de Ignat Iuliana pr
Str General B
DIR
IcircNVĂȚĂM
CH2
CH
CH2
OH
OH
OH
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
mula structurală helliphelliphelliphelliphelliphelliphellip
imice şi condițiile acestora de obţinere a polialco
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
ă de rezolvare se va lua icircn considerare
fesor la Liceul Pedagogic bdquoDP Perpessiciusrdquo
erthelot nr 28-30 Sector 1 010168 Bucureşti
Tel +40 (0)21 40 63 00
wwweduro
ECȚIAGENERALĂ
NT PREUNIVERSITAR
helliphelliphelliphelliphelliphelliphelliphellip 10 puncte
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p
olului de la propenă helliphellip 4 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
Br ăila
8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem
httpslidepdfcomreaderfull2015-chimie-judeteana-clasa-a-xia-subiectebarem 27
ndash H2O230degC
+ 2HA
+ (CH3)
ndash CH3O
Subiectul II helliphelliphelliphelliphelliphelliphelliphelliphellip
A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip1 bdquoParabeniirdquo sunt compuşi ordezinfectanţi şi arome icircn industria
următoarei schemeC6H5ndashOH + KOH A
2 B C + C6H5ndashOH + CO2
C acid pndashhidroxibenzoic
Se cerea Scrieţi ecuaţiile reacţiilor reprezeb Denumiţi conform IUPAC substac Pentru cei doi acizi izomeri din159degC precum și constantele de acid Icircn Australia se interzice folosireainterdicție2 a Scrieți formulele structuralepndashmetoxifenoxid
b Acidul pndashhidroxibenzoic estNaHCO3
HOndashC6
oline OndashC
Ordonați cele patru specii acide icircn oB helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellipUn amestec de acid oxalic și acid foun amestec gazos cu volumul de 06Se cerea Calculați raportul molar al celor db O probă H2C2O4middot2H2O cu masaacidului cristalizat (impuritățile nu r
Subiectul III helliphelliphelliphelliphelliphelliphelliphellip
A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
1 Etanolaminele sunt substanțe foletilenoxid Se introduc icircn soluție apcu o cantitate dublă de etilenoxid gsepară 915 kg monoetanolamina 6Să se calculezea Compoziția icircn procente molare ab Randamentul de transformare a a2 Scrieți ecuațiile reacțiilor posibilde reacție
B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellipIcircntr-un vas cu dop rodat se cacircntăre
brom 005M Se icircnchide vasul și seprin reacția cu excesul de brom colamidon pacircnă la decolorare Calculcondițiile date tiosulfatul de sodiu s
p =
ndash 2KA
Str General B
DIR
IcircNVĂȚĂM
CO2 H2SO4
ndashKHSO4
ROH(H2SO4)
ndashH2O
OSO3
O3H
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellipanici derivaţi de la acidul parahidroxibenzoifarmaceutică cosmetică şi alimentară Aceste s
B acid salicilic
parabeni
E (aromă de anason)
tate icircn schemănţa (E) şi parabenii conservanţi preparaţi cu CH
schemă atribuiți valorile potrivite ale puncteloitate Ka = 105middot10-4 și Ka = 2610-5 Justificați al
parabenilor icircn scopurile enumerate icircn text Form
ale următorilor anioni icircn ordinea creșterii bazi
un acid diprotic pentru care se dau ecuațiile
H4ndashCOOH + HCO3 oline HOndashC6H4ndashCOO oline + H2CH4ndashCOO oline + HCO3 oline HOndashC6H4ndashCOO oline + CO3
2
rdinea descrescătoare a acidității lorhelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
rmic obținut din greșeală se tratează cu 10 g sol72 L (cn) și cu densitatea de 1464 gL (cn)
oi acizi icircn amestece 0130 g este titrată cu 20 mL soluție de KM
eacționează cu KMnO4)
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
site icircn cosmetică industria textilă și de pielărieasă 246 m3 amoniac la temperatura de 27degC șiazos Se obține un amestec al celor trei etanola0 kg dietanolamina și 298 kg trietanolamina
mestecului final de aminoalcoolioniacului și conversia icircn dietanolamină icircntre monoetanolamină (colina) și acid acetic
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellipsc 002 g fenol brut Se adaugă 10 mL acid ac
lasă la icircntuneric 20 minute apoi se adaugă 10orează soluția icircn brun şi se titrează cu soluție daţi puritatea probei de fenol dacă s-au consutransformă icircn Na2S4O6
atm 125degC
erthelot nr 28-30 Sector 1 010168 Bucureşti
Tel +40 (0)21 40 63 00
wwweduro
ECȚIAGENERALĂ
NT PREUNIVERSITAR
helliphelliphelliphelliphelliphelliphelliphellip 25 puncte
helliphelliphelliphelliphelliphelliphelliphellip 15 punctec utilizaţi drept conservanţibstanţe se pot obţine conform
ndash OH respectiv C7H15 ndash OHde topire 213degC și respectiv
egerealați o motivație pentru această
cității fenoxid pndashnitrofenoxid
reacțiilor icircn soluție apoasă de
3 oline
helliphelliphelliphelliphelliphelliphelliphellip 10 puncteuție de H2SO4 95 și se obține
O4 002M Calculați puritatea
helliphelliphelliphelliphelliphelliphellip 25 puncte
helliphelliphelliphelliphelliphelliphelliphellip 10 puncte
care se prepară din amoniac șipresiunea de 10 atm icircmpreună ine din care după distilare se
precizacircnd tipul fiecărui produs
helliphelliphelliphelliphelliphelliphelliphellip 8 punctetic glacial și 25mL soluție de
L soluție KI 1M Iodul formatNa2S2O3 01M icircn prezență deat 13 mL soluție Na2S2O3 Icircn
8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem
httpslidepdfcomreaderfull2015-chimie-judeteana-clasa-a-xia-subiectebarem 37
CH3MgBr (exces) H2O
HO ndash
K2Cr2O7 H+
HCl
C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
Se consideră produsul carbonilicpropionică (A) și acetona (B)
Se cerea Să se indice o schemă de reacțisimultan ambele substanțe (A) și (Bb Să se indice o schemă de reacțiiuna icircn alta
Subiectul IV helliphelliphelliphelliphelliphelliphelliphellip
A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
Substanța (A) are formula moleculcristalizat cu 24 dinitrofenilhidrazide la substanţa (A) se pot scrie ecua
A B D E + NaCl
acetonă + butanal F
F E + H2O
Compusul (B) are formula molec(DNFH) Compusul (E) colorează icirca Scrieți ecuațiile reacțiilor din schb Denumiți conform IUPAC substa
c La dozarea unei soluții a substandin proba de analizat
B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
La echilibrul unei reacţii chimiceCH3COOH 13 moli C2H5OH 23respectivă este 4 Să se calculezeechilibru se mai adaugă 1 mol C2H5
C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
Prin tratarea unui polialcool saturatreprezintă 13695 comparativ cu p
Se cerea Formula moleculară şi structurală b Scrierea ecuaţiilor reacţiilor chiraport cu aerul este 145c Volumul hidrocarburii măsurat lglobal al reacţiilor este 80
Se dau- Mase atomice H - 1 C - 12 N -- Volumul molar V = 224 Lmol- Masa moleculară a aerului microaer =- Constanta universală a gazelor
NOTĂ Timp de lucru 3 ore
Subiecte propuse de Ignat Iuliana
Str General B
DIR
IcircNVĂȚĂM
K2Cr2O7 H+ I2 NaOH
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
u formula moleculară C3H6O sub forma celo
i și condițiile acestora prin care pornind de la
și condițiile lor prin care cele două substanțe (A
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
ră C6H10O2 este neutră față de indicatorii acido a (DNFH) reacționează cu reactiv Tollens și d
iile reacțiilor chimice conform schemei de mai j
C D + CHI3
+ Frsquo
lară C8H18O2 reacționează rapid cu reactivroșu soluția de metilorange și reacționează rapi
mă și cele ale substanței (A) cu DNFH și (A) cunțele notate cu (A) (B) (C) şi (E)
ei (B) se consumă 15mL soluție K2Cr2O7 02M
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
icircntre etanol şi acid acetic compoziţia amestecmoli CH3COOC2H5 şi 23 moli H2O Constan
conversia totală de transformare a acidului acH la volum constant
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
cu anhidridă acidă icircn exces masa moleculară olialcoolul
a polialcooluluiice de obţinere a polialcoolului pornind de la hi
a 1 atm şi 27degC necesar obţinerii a 920 kg po
14 O - 16 Na - 23 S - 32 Cl - 355 K - 39 Cr
2896 gmol= 0082 atmmiddotdm3 molmiddotK
rofesor la Liceul Pedagogic bdquoDP Perpessicius
erthelot nr 28-30 Sector 1 010168 Bucureşti
Tel +40 (0)21 40 63 00
wwweduro
ECȚIAGENERALĂ
NT PREUNIVERSITAR
helliphelliphelliphelliphelliphelliphelliphellip 7 puncte
r doi izomeri ai săi aldehida
un compus unic să se obțină
) și (B) să se poată transforma
helliphelliphelliphelliphelliphelliphellip 30 puncte
helliphelliphelliphelliphelliphelliphelliphellip 15 puncte
- bazici formează un compusreacția iodoformului Pornind
os
ucas dar nu reacționează cucu reactiv Lucas
reactiv Tollens
Calculați masa substanței (B)
helliphelliphelliphelliphelliphelliphelliphellip 5 puncte
lui este următoarea 13 molita de echilibru la temperaturaetic dacă peste amestecul de
helliphelliphelliphelliphelliphelliphelliphellip 10 puncte
reşte cu 126 Această creştere
drocarbura a cărei densitate icircn
lialcool ştiind că randamentul
- 52 Mn - 55 Br - 80 I - 127
Br ăila
8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem
httpslidepdfcomreaderfull2015-chimie-judeteana-clasa-a-xia-subiectebarem 47
ndash H2O
230degC
+ 2HA
+ndash
C
O-
COO-K+
O-K+
OL
BA
Subiectul I helliphelliphelliphelliphelliphelliphelliphelliphellipA helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellipa 4 denumiri conform IUPAC times 1p
b Compusul II prezintă doi diastere
Compusul III prezintă 2 atomi de
2 perechi de
c Explicaţie helliphelliphelliphelliphelliphelliphelliphelliphellip
Asemănarea ndash caracterul ba
Deosebirea ndash Amfetamina (
HCl 5 Tetracaina după acilare
rămacircne solubilă icircn soluţia de HCl 5
B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip1 helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
a mezondash3 4ndashdibromhexan (mezofo
b cisndash2 3ndashbutandiol (mezoformă)
c (plusmn)ndash2 3ndashdimetilhexan (amestec r
d cisndash2ndashbutenă
e (plusmn)transndash1 2ndashciclopentandiol (a
2 Modelarea ecuaţiilor reacţiilor ch
se ca produşi finali de reacţie CH2=
Subiectul II helliphelliphelliphelliphelliphelliphelliphelliphellip
A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
1 a helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
C6H5ndashOH + KOH C6H5ndashO
2
acid pndashhidroxindash 2KA
OH
COO-K+
Str General B
DIR
IcircNVĂȚĂM
+ CO2 H2SO4
ndashKHSO
ROH(H2SO4)
ndashH2O
(CH3)2OSO3 CH3OSO3H
OHO-K+
+
COOR
OH
COOH
OCH3
MPIADA DE CHIMIE ndash etapa jude ţ eană
21 februarie 2015
EM DE EVALUARE ndash CLASA A XI-A
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
oizomeri Z (cis) E (trans) 2 structuri times 1p helliphellip
carbon asimetrici
nantiomeri (eritro plusmn treo plusmn) 4 structuri times 05p
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
zic demonstrat prin scrierea ecuaţiilor reacţiilor c
Benzedrina) după acilare pierde caracterul bazi
avacircnd icircn structura sa grefată şi o grupare amin
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
rmă)
cemic)
estec racemic)
imice degradări Hofmann (metilare urmată de icircn
CH2 şi (CH3)3N helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
oline K+
+ + CO2
benzoic
p = 6 atm 125degC
OH
COO-K+
erthelot nr 28-30 Sector 1 010168 Bucureşti
Tel +40 (0)21 40 63 00
wwweduro
ECȚIAGENERALĂ
NT PREUNIVERSITAR
4
helliphelliphelliphelliphelliphelliphellip 20 punctehelliphelliphelliphelliphelliphelliphelliphellip 12 punctehelliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p
himice
şi este insolubilă icircn soluţia de
o terţiară care nu se acilează
helliphelliphelliphelliphelliphelliphelliphellip 8 punctehelliphelliphelliphelliphelliphelliphelliphelliphelliphellip 5 p
călzire cu Ag(OH)) obţinacircndu-
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 3 p
helliphelliphelliphelliphelliphelliphelliphellip 25 puncte
helliphelliphelliphelliphelliphelliphelliphellip 15 puncte
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 7 p
OH
COOH
8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem
httpslidepdfcomreaderfull2015-chimie-judeteana-clasa-a-xia-subiectebarem 57
OH
COOH
COOH
OH
NO2
O-O-
b (E) acid pndashmetoxibenzoic helliphellip
parahidroxibenzoat de metil helliphelliphellip
parahidroxibenzoat de nndashheptil hellip
c
punct d
punct de to
Ka
Justificare
d Parabenii au potenţial efect cance
2 a helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
lt
b HOndashC6H4ndashCOOH gt H2CO3 gt HC
B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellipa HCOOH rarr CO + H2O hellip
H2C2O4 rarr CO + CO2 + H2
νamestgaze = 003 moli mgaze
b 5 H2C2O4 + 2 KMnO4 + 3 H2SO4
νKMnO4 = 00004 moli m H2C
Subiectul III helliphelliphelliphelliphelliphelliphelliphellip
A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip1 a 3 ecuaţii chimice times 1p helliphelliphellip
Compoziţia icircn procente molare a a
1579 (monoetanolamina)
b η = 95 c= 60 helliphelliphelliphelliphelliphellip
2 4 ecuaţii chimice times 1p helliphelliphelliphellip
B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
C6H5ndashOH + 3Br2 rarr C6H2Br3ndashOH +
Br2 + 2KI rarr 2KBr + I2 helliphelliphelliphellip
I2 + 2Na2S2O3 rarr Na2S4O6 + 2NaI
νNa2S2O3 = 13middot10
-4
moli helliphelliphelliphelliphellip νI2 = νBr2(exces) = 65middot10-4
moli helliphellip
νBr2 icircn reacţia cu fenolul = 6middot10-4
moli helliphellip
p = 94 helliphelliphelliphelliphelliphelliphelliphelliphelliphellip
Str General B
DIR
IcircNVĂȚĂM
O-
CH3O
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
e topire = 159degC
a = 105middot10-4
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
ire = 213degC
26middot10-4
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
rigen datorită nucleului benzenic helliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
lt
O3macr gt HOndashC6H4ndashCOO
macr helliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
09838 g νHCOOH νH2C2O4 = 43 helliphelliphelliphelliphellip
rarr 10 CO2 + K2SO4 + 2MnSO4 + 8 H2Ohelliphelliphellip
2O4middot2H2O = 0126 g p = 96923 helliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
estecului final 6316 (dietanolamina) 2105 (trietanolami
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
3 HBr helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
erthelot nr 28-30 Sector 1 010168 Bucureşti
Tel +40 (0)21 40 63 00
wwweduro
ECȚIAGENERALĂ
NT PREUNIVERSITAR
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphellip 05 p
helliphelliphelliphelliphelliphelliphelliphelliphellip 05 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p helliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphellip 10 punctehelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p
helliphelliphelliphelliphelliphelliphellip 25 puncte
helliphelliphelliphelliphelliphelliphelliphellip 10 punctehelliphelliphelliphelliphelliphelliphelliphelliphelliphellip 3 p
a) helliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p
helliphelliphelliphelliphelliphelliphelliphellip 8 puncte
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 phelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem
httpslidepdfcomreaderfull2015-chimie-judeteana-clasa-a-xia-subiectebarem 67
CH3
CH2
CH
OH
CHCCH3
CH3
OH
CH3
C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
a Modelarea ecuaţiilor reacţiilor
ozonizare urmată de hidroliză helliphellip
b Ararr helliprarr B helliphelliphelliphelliphellip
Brarr helliprarr A helliphelliphelliphelliphellip
Subiectul IV helliphelliphelliphelliphelliphelliphelliphellip
A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
a 8 ecuaţii chimice times 1p helliphelliphelliphellip
(A) (
(E)
b 4 denumiri conform IUPAC times 1p
(A) 2ndashetilndash3ndashoxondashbutanal
(B) 3ndashetilndash2 metilndash2 4ndashpentandiol
(C) 3ndashetilndash4 metilndash4ndashhidroxindash2ndashpe
(E) acid 2ndashetilndash3ndashmetilndash3ndashhidroxib
c
3 + K
νK2Cr2O7 = 0003 moli νB= 0009 mo
B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
Ctotal = 1
3
∙100
Ctotal = 8447 helliphelliphelliphelliphelliphelliphelliphellip
CH3 C CH
O
CHO
CH2
CH3
OH
CCH3
CH
C
O
CH3
CH2OH
CHCCH3
CH3
OH CH3
CH3 C CH CH2 C
CH3
Str General B
DIR
IcircNVĂȚĂM
C
CH3
CH3 C CH
OH CH2
CH3
O
C
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
himice şi condițiile acestora Se poate porni
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphellip
(A)
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
B) (C)
(F)
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
tanonă
utanoic
2Cr2O7 + 4H2SO4 3
hellip
l mB = 1314 g helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
CH3
CH2
CHCH
OH
CH3 CH
CH3
CH3 C CH
OH CH2
CH3
O
C
C
CH3
CH2OH
CHC
CH3
O
H CH2CH3 CH2
3 CH2CH3
erthelot nr 28-30 Sector 1 010168 Bucureşti
Tel +40 (0)21 40 63 00
wwweduro
ECȚIAGENERALĂ
NT PREUNIVERSITAR
O
CH3CCH3
H3
helliphelliphelliphelliphelliphelliphelliphellip 7 puncte
de la 2ndashmetilndash2ndashpentenă prin
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 3 p
(B)
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
helliphelliphelliphelliphelliphelliphellip 30 puncte
helliphelliphelliphelliphelliphelliphelliphellip 15 puncte
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 8 p
(D)
(Frsquo)
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p
+ K2SO4 + Cr2(SO4)3 + 7 H2O
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
helliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphellip 5 puncte
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 5 p
C
CH3
CH2OH
CHCCH3
CH3 O
O-Na+
O
H
C CH2
OH CH3
C
+ CHO
8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem
httpslidepdfcomreaderfull2015-chimie-judeteana-clasa-a-xia-subiectebarem 77
C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
a Formula moleculară C3H8O3 For
b Modelarea ecuaţiilor reacţiilor ch
c VC3H6(1 atm 27degC) = 30769 m3 helliphellip
NOTĂ Orice altă variantă corect
Barem elaborat de Ignat Iuliana pr
Str General B
DIR
IcircNVĂȚĂM
CH2
CH
CH2
OH
OH
OH
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
mula structurală helliphelliphelliphelliphelliphelliphellip
imice şi condițiile acestora de obţinere a polialco
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
ă de rezolvare se va lua icircn considerare
fesor la Liceul Pedagogic bdquoDP Perpessiciusrdquo
erthelot nr 28-30 Sector 1 010168 Bucureşti
Tel +40 (0)21 40 63 00
wwweduro
ECȚIAGENERALĂ
NT PREUNIVERSITAR
helliphelliphelliphelliphelliphelliphelliphellip 10 puncte
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p
olului de la propenă helliphellip 4 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
Br ăila
8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem
httpslidepdfcomreaderfull2015-chimie-judeteana-clasa-a-xia-subiectebarem 37
CH3MgBr (exces) H2O
HO ndash
K2Cr2O7 H+
HCl
C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
Se consideră produsul carbonilicpropionică (A) și acetona (B)
Se cerea Să se indice o schemă de reacțisimultan ambele substanțe (A) și (Bb Să se indice o schemă de reacțiiuna icircn alta
Subiectul IV helliphelliphelliphelliphelliphelliphelliphellip
A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
Substanța (A) are formula moleculcristalizat cu 24 dinitrofenilhidrazide la substanţa (A) se pot scrie ecua
A B D E + NaCl
acetonă + butanal F
F E + H2O
Compusul (B) are formula molec(DNFH) Compusul (E) colorează icirca Scrieți ecuațiile reacțiilor din schb Denumiți conform IUPAC substa
c La dozarea unei soluții a substandin proba de analizat
B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
La echilibrul unei reacţii chimiceCH3COOH 13 moli C2H5OH 23respectivă este 4 Să se calculezeechilibru se mai adaugă 1 mol C2H5
C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
Prin tratarea unui polialcool saturatreprezintă 13695 comparativ cu p
Se cerea Formula moleculară şi structurală b Scrierea ecuaţiilor reacţiilor chiraport cu aerul este 145c Volumul hidrocarburii măsurat lglobal al reacţiilor este 80
Se dau- Mase atomice H - 1 C - 12 N -- Volumul molar V = 224 Lmol- Masa moleculară a aerului microaer =- Constanta universală a gazelor
NOTĂ Timp de lucru 3 ore
Subiecte propuse de Ignat Iuliana
Str General B
DIR
IcircNVĂȚĂM
K2Cr2O7 H+ I2 NaOH
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
u formula moleculară C3H6O sub forma celo
i și condițiile acestora prin care pornind de la
și condițiile lor prin care cele două substanțe (A
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
ră C6H10O2 este neutră față de indicatorii acido a (DNFH) reacționează cu reactiv Tollens și d
iile reacțiilor chimice conform schemei de mai j
C D + CHI3
+ Frsquo
lară C8H18O2 reacționează rapid cu reactivroșu soluția de metilorange și reacționează rapi
mă și cele ale substanței (A) cu DNFH și (A) cunțele notate cu (A) (B) (C) şi (E)
ei (B) se consumă 15mL soluție K2Cr2O7 02M
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
icircntre etanol şi acid acetic compoziţia amestecmoli CH3COOC2H5 şi 23 moli H2O Constan
conversia totală de transformare a acidului acH la volum constant
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
cu anhidridă acidă icircn exces masa moleculară olialcoolul
a polialcooluluiice de obţinere a polialcoolului pornind de la hi
a 1 atm şi 27degC necesar obţinerii a 920 kg po
14 O - 16 Na - 23 S - 32 Cl - 355 K - 39 Cr
2896 gmol= 0082 atmmiddotdm3 molmiddotK
rofesor la Liceul Pedagogic bdquoDP Perpessicius
erthelot nr 28-30 Sector 1 010168 Bucureşti
Tel +40 (0)21 40 63 00
wwweduro
ECȚIAGENERALĂ
NT PREUNIVERSITAR
helliphelliphelliphelliphelliphelliphelliphellip 7 puncte
r doi izomeri ai săi aldehida
un compus unic să se obțină
) și (B) să se poată transforma
helliphelliphelliphelliphelliphelliphellip 30 puncte
helliphelliphelliphelliphelliphelliphelliphellip 15 puncte
- bazici formează un compusreacția iodoformului Pornind
os
ucas dar nu reacționează cucu reactiv Lucas
reactiv Tollens
Calculați masa substanței (B)
helliphelliphelliphelliphelliphelliphelliphellip 5 puncte
lui este următoarea 13 molita de echilibru la temperaturaetic dacă peste amestecul de
helliphelliphelliphelliphelliphelliphelliphellip 10 puncte
reşte cu 126 Această creştere
drocarbura a cărei densitate icircn
lialcool ştiind că randamentul
- 52 Mn - 55 Br - 80 I - 127
Br ăila
8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem
httpslidepdfcomreaderfull2015-chimie-judeteana-clasa-a-xia-subiectebarem 47
ndash H2O
230degC
+ 2HA
+ndash
C
O-
COO-K+
O-K+
OL
BA
Subiectul I helliphelliphelliphelliphelliphelliphelliphelliphellipA helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellipa 4 denumiri conform IUPAC times 1p
b Compusul II prezintă doi diastere
Compusul III prezintă 2 atomi de
2 perechi de
c Explicaţie helliphelliphelliphelliphelliphelliphelliphelliphellip
Asemănarea ndash caracterul ba
Deosebirea ndash Amfetamina (
HCl 5 Tetracaina după acilare
rămacircne solubilă icircn soluţia de HCl 5
B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip1 helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
a mezondash3 4ndashdibromhexan (mezofo
b cisndash2 3ndashbutandiol (mezoformă)
c (plusmn)ndash2 3ndashdimetilhexan (amestec r
d cisndash2ndashbutenă
e (plusmn)transndash1 2ndashciclopentandiol (a
2 Modelarea ecuaţiilor reacţiilor ch
se ca produşi finali de reacţie CH2=
Subiectul II helliphelliphelliphelliphelliphelliphelliphelliphellip
A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
1 a helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
C6H5ndashOH + KOH C6H5ndashO
2
acid pndashhidroxindash 2KA
OH
COO-K+
Str General B
DIR
IcircNVĂȚĂM
+ CO2 H2SO4
ndashKHSO
ROH(H2SO4)
ndashH2O
(CH3)2OSO3 CH3OSO3H
OHO-K+
+
COOR
OH
COOH
OCH3
MPIADA DE CHIMIE ndash etapa jude ţ eană
21 februarie 2015
EM DE EVALUARE ndash CLASA A XI-A
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
oizomeri Z (cis) E (trans) 2 structuri times 1p helliphellip
carbon asimetrici
nantiomeri (eritro plusmn treo plusmn) 4 structuri times 05p
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
zic demonstrat prin scrierea ecuaţiilor reacţiilor c
Benzedrina) după acilare pierde caracterul bazi
avacircnd icircn structura sa grefată şi o grupare amin
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
rmă)
cemic)
estec racemic)
imice degradări Hofmann (metilare urmată de icircn
CH2 şi (CH3)3N helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
oline K+
+ + CO2
benzoic
p = 6 atm 125degC
OH
COO-K+
erthelot nr 28-30 Sector 1 010168 Bucureşti
Tel +40 (0)21 40 63 00
wwweduro
ECȚIAGENERALĂ
NT PREUNIVERSITAR
4
helliphelliphelliphelliphelliphelliphellip 20 punctehelliphelliphelliphelliphelliphelliphelliphellip 12 punctehelliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p
himice
şi este insolubilă icircn soluţia de
o terţiară care nu se acilează
helliphelliphelliphelliphelliphelliphelliphellip 8 punctehelliphelliphelliphelliphelliphelliphelliphelliphelliphellip 5 p
călzire cu Ag(OH)) obţinacircndu-
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 3 p
helliphelliphelliphelliphelliphelliphelliphellip 25 puncte
helliphelliphelliphelliphelliphelliphelliphellip 15 puncte
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 7 p
OH
COOH
8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem
httpslidepdfcomreaderfull2015-chimie-judeteana-clasa-a-xia-subiectebarem 57
OH
COOH
COOH
OH
NO2
O-O-
b (E) acid pndashmetoxibenzoic helliphellip
parahidroxibenzoat de metil helliphelliphellip
parahidroxibenzoat de nndashheptil hellip
c
punct d
punct de to
Ka
Justificare
d Parabenii au potenţial efect cance
2 a helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
lt
b HOndashC6H4ndashCOOH gt H2CO3 gt HC
B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellipa HCOOH rarr CO + H2O hellip
H2C2O4 rarr CO + CO2 + H2
νamestgaze = 003 moli mgaze
b 5 H2C2O4 + 2 KMnO4 + 3 H2SO4
νKMnO4 = 00004 moli m H2C
Subiectul III helliphelliphelliphelliphelliphelliphelliphellip
A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip1 a 3 ecuaţii chimice times 1p helliphelliphellip
Compoziţia icircn procente molare a a
1579 (monoetanolamina)
b η = 95 c= 60 helliphelliphelliphelliphelliphellip
2 4 ecuaţii chimice times 1p helliphelliphelliphellip
B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
C6H5ndashOH + 3Br2 rarr C6H2Br3ndashOH +
Br2 + 2KI rarr 2KBr + I2 helliphelliphelliphellip
I2 + 2Na2S2O3 rarr Na2S4O6 + 2NaI
νNa2S2O3 = 13middot10
-4
moli helliphelliphelliphelliphellip νI2 = νBr2(exces) = 65middot10-4
moli helliphellip
νBr2 icircn reacţia cu fenolul = 6middot10-4
moli helliphellip
p = 94 helliphelliphelliphelliphelliphelliphelliphelliphelliphellip
Str General B
DIR
IcircNVĂȚĂM
O-
CH3O
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
e topire = 159degC
a = 105middot10-4
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
ire = 213degC
26middot10-4
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
rigen datorită nucleului benzenic helliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
lt
O3macr gt HOndashC6H4ndashCOO
macr helliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
09838 g νHCOOH νH2C2O4 = 43 helliphelliphelliphelliphellip
rarr 10 CO2 + K2SO4 + 2MnSO4 + 8 H2Ohelliphelliphellip
2O4middot2H2O = 0126 g p = 96923 helliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
estecului final 6316 (dietanolamina) 2105 (trietanolami
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
3 HBr helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
erthelot nr 28-30 Sector 1 010168 Bucureşti
Tel +40 (0)21 40 63 00
wwweduro
ECȚIAGENERALĂ
NT PREUNIVERSITAR
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphellip 05 p
helliphelliphelliphelliphelliphelliphelliphelliphellip 05 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p helliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphellip 10 punctehelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p
helliphelliphelliphelliphelliphelliphellip 25 puncte
helliphelliphelliphelliphelliphelliphelliphellip 10 punctehelliphelliphelliphelliphelliphelliphelliphelliphelliphellip 3 p
a) helliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p
helliphelliphelliphelliphelliphelliphelliphellip 8 puncte
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 phelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem
httpslidepdfcomreaderfull2015-chimie-judeteana-clasa-a-xia-subiectebarem 67
CH3
CH2
CH
OH
CHCCH3
CH3
OH
CH3
C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
a Modelarea ecuaţiilor reacţiilor
ozonizare urmată de hidroliză helliphellip
b Ararr helliprarr B helliphelliphelliphelliphellip
Brarr helliprarr A helliphelliphelliphelliphellip
Subiectul IV helliphelliphelliphelliphelliphelliphelliphellip
A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
a 8 ecuaţii chimice times 1p helliphelliphelliphellip
(A) (
(E)
b 4 denumiri conform IUPAC times 1p
(A) 2ndashetilndash3ndashoxondashbutanal
(B) 3ndashetilndash2 metilndash2 4ndashpentandiol
(C) 3ndashetilndash4 metilndash4ndashhidroxindash2ndashpe
(E) acid 2ndashetilndash3ndashmetilndash3ndashhidroxib
c
3 + K
νK2Cr2O7 = 0003 moli νB= 0009 mo
B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
Ctotal = 1
3
∙100
Ctotal = 8447 helliphelliphelliphelliphelliphelliphelliphellip
CH3 C CH
O
CHO
CH2
CH3
OH
CCH3
CH
C
O
CH3
CH2OH
CHCCH3
CH3
OH CH3
CH3 C CH CH2 C
CH3
Str General B
DIR
IcircNVĂȚĂM
C
CH3
CH3 C CH
OH CH2
CH3
O
C
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
himice şi condițiile acestora Se poate porni
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphellip
(A)
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
B) (C)
(F)
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
tanonă
utanoic
2Cr2O7 + 4H2SO4 3
hellip
l mB = 1314 g helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
CH3
CH2
CHCH
OH
CH3 CH
CH3
CH3 C CH
OH CH2
CH3
O
C
C
CH3
CH2OH
CHC
CH3
O
H CH2CH3 CH2
3 CH2CH3
erthelot nr 28-30 Sector 1 010168 Bucureşti
Tel +40 (0)21 40 63 00
wwweduro
ECȚIAGENERALĂ
NT PREUNIVERSITAR
O
CH3CCH3
H3
helliphelliphelliphelliphelliphelliphelliphellip 7 puncte
de la 2ndashmetilndash2ndashpentenă prin
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 3 p
(B)
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
helliphelliphelliphelliphelliphelliphellip 30 puncte
helliphelliphelliphelliphelliphelliphelliphellip 15 puncte
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 8 p
(D)
(Frsquo)
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p
+ K2SO4 + Cr2(SO4)3 + 7 H2O
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
helliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphellip 5 puncte
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 5 p
C
CH3
CH2OH
CHCCH3
CH3 O
O-Na+
O
H
C CH2
OH CH3
C
+ CHO
8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem
httpslidepdfcomreaderfull2015-chimie-judeteana-clasa-a-xia-subiectebarem 77
C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
a Formula moleculară C3H8O3 For
b Modelarea ecuaţiilor reacţiilor ch
c VC3H6(1 atm 27degC) = 30769 m3 helliphellip
NOTĂ Orice altă variantă corect
Barem elaborat de Ignat Iuliana pr
Str General B
DIR
IcircNVĂȚĂM
CH2
CH
CH2
OH
OH
OH
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
mula structurală helliphelliphelliphelliphelliphelliphellip
imice şi condițiile acestora de obţinere a polialco
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
ă de rezolvare se va lua icircn considerare
fesor la Liceul Pedagogic bdquoDP Perpessiciusrdquo
erthelot nr 28-30 Sector 1 010168 Bucureşti
Tel +40 (0)21 40 63 00
wwweduro
ECȚIAGENERALĂ
NT PREUNIVERSITAR
helliphelliphelliphelliphelliphelliphelliphellip 10 puncte
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p
olului de la propenă helliphellip 4 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
Br ăila
8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem
httpslidepdfcomreaderfull2015-chimie-judeteana-clasa-a-xia-subiectebarem 47
ndash H2O
230degC
+ 2HA
+ndash
C
O-
COO-K+
O-K+
OL
BA
Subiectul I helliphelliphelliphelliphelliphelliphelliphelliphellipA helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellipa 4 denumiri conform IUPAC times 1p
b Compusul II prezintă doi diastere
Compusul III prezintă 2 atomi de
2 perechi de
c Explicaţie helliphelliphelliphelliphelliphelliphelliphelliphellip
Asemănarea ndash caracterul ba
Deosebirea ndash Amfetamina (
HCl 5 Tetracaina după acilare
rămacircne solubilă icircn soluţia de HCl 5
B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip1 helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
a mezondash3 4ndashdibromhexan (mezofo
b cisndash2 3ndashbutandiol (mezoformă)
c (plusmn)ndash2 3ndashdimetilhexan (amestec r
d cisndash2ndashbutenă
e (plusmn)transndash1 2ndashciclopentandiol (a
2 Modelarea ecuaţiilor reacţiilor ch
se ca produşi finali de reacţie CH2=
Subiectul II helliphelliphelliphelliphelliphelliphelliphelliphellip
A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
1 a helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
C6H5ndashOH + KOH C6H5ndashO
2
acid pndashhidroxindash 2KA
OH
COO-K+
Str General B
DIR
IcircNVĂȚĂM
+ CO2 H2SO4
ndashKHSO
ROH(H2SO4)
ndashH2O
(CH3)2OSO3 CH3OSO3H
OHO-K+
+
COOR
OH
COOH
OCH3
MPIADA DE CHIMIE ndash etapa jude ţ eană
21 februarie 2015
EM DE EVALUARE ndash CLASA A XI-A
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
oizomeri Z (cis) E (trans) 2 structuri times 1p helliphellip
carbon asimetrici
nantiomeri (eritro plusmn treo plusmn) 4 structuri times 05p
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
zic demonstrat prin scrierea ecuaţiilor reacţiilor c
Benzedrina) după acilare pierde caracterul bazi
avacircnd icircn structura sa grefată şi o grupare amin
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
rmă)
cemic)
estec racemic)
imice degradări Hofmann (metilare urmată de icircn
CH2 şi (CH3)3N helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
oline K+
+ + CO2
benzoic
p = 6 atm 125degC
OH
COO-K+
erthelot nr 28-30 Sector 1 010168 Bucureşti
Tel +40 (0)21 40 63 00
wwweduro
ECȚIAGENERALĂ
NT PREUNIVERSITAR
4
helliphelliphelliphelliphelliphelliphellip 20 punctehelliphelliphelliphelliphelliphelliphelliphellip 12 punctehelliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p
himice
şi este insolubilă icircn soluţia de
o terţiară care nu se acilează
helliphelliphelliphelliphelliphelliphelliphellip 8 punctehelliphelliphelliphelliphelliphelliphelliphelliphelliphellip 5 p
călzire cu Ag(OH)) obţinacircndu-
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 3 p
helliphelliphelliphelliphelliphelliphelliphellip 25 puncte
helliphelliphelliphelliphelliphelliphelliphellip 15 puncte
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 7 p
OH
COOH
8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem
httpslidepdfcomreaderfull2015-chimie-judeteana-clasa-a-xia-subiectebarem 57
OH
COOH
COOH
OH
NO2
O-O-
b (E) acid pndashmetoxibenzoic helliphellip
parahidroxibenzoat de metil helliphelliphellip
parahidroxibenzoat de nndashheptil hellip
c
punct d
punct de to
Ka
Justificare
d Parabenii au potenţial efect cance
2 a helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
lt
b HOndashC6H4ndashCOOH gt H2CO3 gt HC
B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellipa HCOOH rarr CO + H2O hellip
H2C2O4 rarr CO + CO2 + H2
νamestgaze = 003 moli mgaze
b 5 H2C2O4 + 2 KMnO4 + 3 H2SO4
νKMnO4 = 00004 moli m H2C
Subiectul III helliphelliphelliphelliphelliphelliphelliphellip
A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip1 a 3 ecuaţii chimice times 1p helliphelliphellip
Compoziţia icircn procente molare a a
1579 (monoetanolamina)
b η = 95 c= 60 helliphelliphelliphelliphelliphellip
2 4 ecuaţii chimice times 1p helliphelliphelliphellip
B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
C6H5ndashOH + 3Br2 rarr C6H2Br3ndashOH +
Br2 + 2KI rarr 2KBr + I2 helliphelliphelliphellip
I2 + 2Na2S2O3 rarr Na2S4O6 + 2NaI
νNa2S2O3 = 13middot10
-4
moli helliphelliphelliphelliphellip νI2 = νBr2(exces) = 65middot10-4
moli helliphellip
νBr2 icircn reacţia cu fenolul = 6middot10-4
moli helliphellip
p = 94 helliphelliphelliphelliphelliphelliphelliphelliphelliphellip
Str General B
DIR
IcircNVĂȚĂM
O-
CH3O
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
e topire = 159degC
a = 105middot10-4
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
ire = 213degC
26middot10-4
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
rigen datorită nucleului benzenic helliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
lt
O3macr gt HOndashC6H4ndashCOO
macr helliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
09838 g νHCOOH νH2C2O4 = 43 helliphelliphelliphelliphellip
rarr 10 CO2 + K2SO4 + 2MnSO4 + 8 H2Ohelliphelliphellip
2O4middot2H2O = 0126 g p = 96923 helliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
estecului final 6316 (dietanolamina) 2105 (trietanolami
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
3 HBr helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
erthelot nr 28-30 Sector 1 010168 Bucureşti
Tel +40 (0)21 40 63 00
wwweduro
ECȚIAGENERALĂ
NT PREUNIVERSITAR
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphellip 05 p
helliphelliphelliphelliphelliphelliphelliphelliphellip 05 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p helliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphellip 10 punctehelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p
helliphelliphelliphelliphelliphelliphellip 25 puncte
helliphelliphelliphelliphelliphelliphelliphellip 10 punctehelliphelliphelliphelliphelliphelliphelliphelliphelliphellip 3 p
a) helliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p
helliphelliphelliphelliphelliphelliphelliphellip 8 puncte
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 phelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem
httpslidepdfcomreaderfull2015-chimie-judeteana-clasa-a-xia-subiectebarem 67
CH3
CH2
CH
OH
CHCCH3
CH3
OH
CH3
C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
a Modelarea ecuaţiilor reacţiilor
ozonizare urmată de hidroliză helliphellip
b Ararr helliprarr B helliphelliphelliphelliphellip
Brarr helliprarr A helliphelliphelliphelliphellip
Subiectul IV helliphelliphelliphelliphelliphelliphelliphellip
A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
a 8 ecuaţii chimice times 1p helliphelliphelliphellip
(A) (
(E)
b 4 denumiri conform IUPAC times 1p
(A) 2ndashetilndash3ndashoxondashbutanal
(B) 3ndashetilndash2 metilndash2 4ndashpentandiol
(C) 3ndashetilndash4 metilndash4ndashhidroxindash2ndashpe
(E) acid 2ndashetilndash3ndashmetilndash3ndashhidroxib
c
3 + K
νK2Cr2O7 = 0003 moli νB= 0009 mo
B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
Ctotal = 1
3
∙100
Ctotal = 8447 helliphelliphelliphelliphelliphelliphelliphellip
CH3 C CH
O
CHO
CH2
CH3
OH
CCH3
CH
C
O
CH3
CH2OH
CHCCH3
CH3
OH CH3
CH3 C CH CH2 C
CH3
Str General B
DIR
IcircNVĂȚĂM
C
CH3
CH3 C CH
OH CH2
CH3
O
C
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
himice şi condițiile acestora Se poate porni
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphellip
(A)
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
B) (C)
(F)
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
tanonă
utanoic
2Cr2O7 + 4H2SO4 3
hellip
l mB = 1314 g helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
CH3
CH2
CHCH
OH
CH3 CH
CH3
CH3 C CH
OH CH2
CH3
O
C
C
CH3
CH2OH
CHC
CH3
O
H CH2CH3 CH2
3 CH2CH3
erthelot nr 28-30 Sector 1 010168 Bucureşti
Tel +40 (0)21 40 63 00
wwweduro
ECȚIAGENERALĂ
NT PREUNIVERSITAR
O
CH3CCH3
H3
helliphelliphelliphelliphelliphelliphelliphellip 7 puncte
de la 2ndashmetilndash2ndashpentenă prin
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 3 p
(B)
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
helliphelliphelliphelliphelliphelliphellip 30 puncte
helliphelliphelliphelliphelliphelliphelliphellip 15 puncte
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 8 p
(D)
(Frsquo)
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p
+ K2SO4 + Cr2(SO4)3 + 7 H2O
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
helliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphellip 5 puncte
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 5 p
C
CH3
CH2OH
CHCCH3
CH3 O
O-Na+
O
H
C CH2
OH CH3
C
+ CHO
8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem
httpslidepdfcomreaderfull2015-chimie-judeteana-clasa-a-xia-subiectebarem 77
C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
a Formula moleculară C3H8O3 For
b Modelarea ecuaţiilor reacţiilor ch
c VC3H6(1 atm 27degC) = 30769 m3 helliphellip
NOTĂ Orice altă variantă corect
Barem elaborat de Ignat Iuliana pr
Str General B
DIR
IcircNVĂȚĂM
CH2
CH
CH2
OH
OH
OH
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
mula structurală helliphelliphelliphelliphelliphelliphellip
imice şi condițiile acestora de obţinere a polialco
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
ă de rezolvare se va lua icircn considerare
fesor la Liceul Pedagogic bdquoDP Perpessiciusrdquo
erthelot nr 28-30 Sector 1 010168 Bucureşti
Tel +40 (0)21 40 63 00
wwweduro
ECȚIAGENERALĂ
NT PREUNIVERSITAR
helliphelliphelliphelliphelliphelliphelliphellip 10 puncte
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p
olului de la propenă helliphellip 4 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
Br ăila
8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem
httpslidepdfcomreaderfull2015-chimie-judeteana-clasa-a-xia-subiectebarem 57
OH
COOH
COOH
OH
NO2
O-O-
b (E) acid pndashmetoxibenzoic helliphellip
parahidroxibenzoat de metil helliphelliphellip
parahidroxibenzoat de nndashheptil hellip
c
punct d
punct de to
Ka
Justificare
d Parabenii au potenţial efect cance
2 a helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
lt
b HOndashC6H4ndashCOOH gt H2CO3 gt HC
B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellipa HCOOH rarr CO + H2O hellip
H2C2O4 rarr CO + CO2 + H2
νamestgaze = 003 moli mgaze
b 5 H2C2O4 + 2 KMnO4 + 3 H2SO4
νKMnO4 = 00004 moli m H2C
Subiectul III helliphelliphelliphelliphelliphelliphelliphellip
A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip1 a 3 ecuaţii chimice times 1p helliphelliphellip
Compoziţia icircn procente molare a a
1579 (monoetanolamina)
b η = 95 c= 60 helliphelliphelliphelliphelliphellip
2 4 ecuaţii chimice times 1p helliphelliphelliphellip
B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
C6H5ndashOH + 3Br2 rarr C6H2Br3ndashOH +
Br2 + 2KI rarr 2KBr + I2 helliphelliphelliphellip
I2 + 2Na2S2O3 rarr Na2S4O6 + 2NaI
νNa2S2O3 = 13middot10
-4
moli helliphelliphelliphelliphellip νI2 = νBr2(exces) = 65middot10-4
moli helliphellip
νBr2 icircn reacţia cu fenolul = 6middot10-4
moli helliphellip
p = 94 helliphelliphelliphelliphelliphelliphelliphelliphelliphellip
Str General B
DIR
IcircNVĂȚĂM
O-
CH3O
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
e topire = 159degC
a = 105middot10-4
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
ire = 213degC
26middot10-4
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
rigen datorită nucleului benzenic helliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
lt
O3macr gt HOndashC6H4ndashCOO
macr helliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
09838 g νHCOOH νH2C2O4 = 43 helliphelliphelliphelliphellip
rarr 10 CO2 + K2SO4 + 2MnSO4 + 8 H2Ohelliphelliphellip
2O4middot2H2O = 0126 g p = 96923 helliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
estecului final 6316 (dietanolamina) 2105 (trietanolami
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
3 HBr helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
erthelot nr 28-30 Sector 1 010168 Bucureşti
Tel +40 (0)21 40 63 00
wwweduro
ECȚIAGENERALĂ
NT PREUNIVERSITAR
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphellip 05 p
helliphelliphelliphelliphelliphelliphelliphelliphellip 05 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p helliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphellip 10 punctehelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p
helliphelliphelliphelliphelliphelliphellip 25 puncte
helliphelliphelliphelliphelliphelliphelliphellip 10 punctehelliphelliphelliphelliphelliphelliphelliphelliphelliphellip 3 p
a) helliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p
helliphelliphelliphelliphelliphelliphelliphellip 8 puncte
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 phelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem
httpslidepdfcomreaderfull2015-chimie-judeteana-clasa-a-xia-subiectebarem 67
CH3
CH2
CH
OH
CHCCH3
CH3
OH
CH3
C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
a Modelarea ecuaţiilor reacţiilor
ozonizare urmată de hidroliză helliphellip
b Ararr helliprarr B helliphelliphelliphelliphellip
Brarr helliprarr A helliphelliphelliphelliphellip
Subiectul IV helliphelliphelliphelliphelliphelliphelliphellip
A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
a 8 ecuaţii chimice times 1p helliphelliphelliphellip
(A) (
(E)
b 4 denumiri conform IUPAC times 1p
(A) 2ndashetilndash3ndashoxondashbutanal
(B) 3ndashetilndash2 metilndash2 4ndashpentandiol
(C) 3ndashetilndash4 metilndash4ndashhidroxindash2ndashpe
(E) acid 2ndashetilndash3ndashmetilndash3ndashhidroxib
c
3 + K
νK2Cr2O7 = 0003 moli νB= 0009 mo
B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
Ctotal = 1
3
∙100
Ctotal = 8447 helliphelliphelliphelliphelliphelliphelliphellip
CH3 C CH
O
CHO
CH2
CH3
OH
CCH3
CH
C
O
CH3
CH2OH
CHCCH3
CH3
OH CH3
CH3 C CH CH2 C
CH3
Str General B
DIR
IcircNVĂȚĂM
C
CH3
CH3 C CH
OH CH2
CH3
O
C
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
himice şi condițiile acestora Se poate porni
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphellip
(A)
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
B) (C)
(F)
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
tanonă
utanoic
2Cr2O7 + 4H2SO4 3
hellip
l mB = 1314 g helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
CH3
CH2
CHCH
OH
CH3 CH
CH3
CH3 C CH
OH CH2
CH3
O
C
C
CH3
CH2OH
CHC
CH3
O
H CH2CH3 CH2
3 CH2CH3
erthelot nr 28-30 Sector 1 010168 Bucureşti
Tel +40 (0)21 40 63 00
wwweduro
ECȚIAGENERALĂ
NT PREUNIVERSITAR
O
CH3CCH3
H3
helliphelliphelliphelliphelliphelliphelliphellip 7 puncte
de la 2ndashmetilndash2ndashpentenă prin
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 3 p
(B)
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
helliphelliphelliphelliphelliphelliphellip 30 puncte
helliphelliphelliphelliphelliphelliphelliphellip 15 puncte
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 8 p
(D)
(Frsquo)
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p
+ K2SO4 + Cr2(SO4)3 + 7 H2O
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
helliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphellip 5 puncte
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 5 p
C
CH3
CH2OH
CHCCH3
CH3 O
O-Na+
O
H
C CH2
OH CH3
C
+ CHO
8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem
httpslidepdfcomreaderfull2015-chimie-judeteana-clasa-a-xia-subiectebarem 77
C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
a Formula moleculară C3H8O3 For
b Modelarea ecuaţiilor reacţiilor ch
c VC3H6(1 atm 27degC) = 30769 m3 helliphellip
NOTĂ Orice altă variantă corect
Barem elaborat de Ignat Iuliana pr
Str General B
DIR
IcircNVĂȚĂM
CH2
CH
CH2
OH
OH
OH
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
mula structurală helliphelliphelliphelliphelliphelliphellip
imice şi condițiile acestora de obţinere a polialco
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
ă de rezolvare se va lua icircn considerare
fesor la Liceul Pedagogic bdquoDP Perpessiciusrdquo
erthelot nr 28-30 Sector 1 010168 Bucureşti
Tel +40 (0)21 40 63 00
wwweduro
ECȚIAGENERALĂ
NT PREUNIVERSITAR
helliphelliphelliphelliphelliphelliphelliphellip 10 puncte
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p
olului de la propenă helliphellip 4 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
Br ăila
8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem
httpslidepdfcomreaderfull2015-chimie-judeteana-clasa-a-xia-subiectebarem 67
CH3
CH2
CH
OH
CHCCH3
CH3
OH
CH3
C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
a Modelarea ecuaţiilor reacţiilor
ozonizare urmată de hidroliză helliphellip
b Ararr helliprarr B helliphelliphelliphelliphellip
Brarr helliprarr A helliphelliphelliphelliphellip
Subiectul IV helliphelliphelliphelliphelliphelliphelliphellip
A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
a 8 ecuaţii chimice times 1p helliphelliphelliphellip
(A) (
(E)
b 4 denumiri conform IUPAC times 1p
(A) 2ndashetilndash3ndashoxondashbutanal
(B) 3ndashetilndash2 metilndash2 4ndashpentandiol
(C) 3ndashetilndash4 metilndash4ndashhidroxindash2ndashpe
(E) acid 2ndashetilndash3ndashmetilndash3ndashhidroxib
c
3 + K
νK2Cr2O7 = 0003 moli νB= 0009 mo
B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
Ctotal = 1
3
∙100
Ctotal = 8447 helliphelliphelliphelliphelliphelliphelliphellip
CH3 C CH
O
CHO
CH2
CH3
OH
CCH3
CH
C
O
CH3
CH2OH
CHCCH3
CH3
OH CH3
CH3 C CH CH2 C
CH3
Str General B
DIR
IcircNVĂȚĂM
C
CH3
CH3 C CH
OH CH2
CH3
O
C
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
himice şi condițiile acestora Se poate porni
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphellip
(A)
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
B) (C)
(F)
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
tanonă
utanoic
2Cr2O7 + 4H2SO4 3
hellip
l mB = 1314 g helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
CH3
CH2
CHCH
OH
CH3 CH
CH3
CH3 C CH
OH CH2
CH3
O
C
C
CH3
CH2OH
CHC
CH3
O
H CH2CH3 CH2
3 CH2CH3
erthelot nr 28-30 Sector 1 010168 Bucureşti
Tel +40 (0)21 40 63 00
wwweduro
ECȚIAGENERALĂ
NT PREUNIVERSITAR
O
CH3CCH3
H3
helliphelliphelliphelliphelliphelliphelliphellip 7 puncte
de la 2ndashmetilndash2ndashpentenă prin
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 3 p
(B)
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
helliphelliphelliphelliphelliphelliphellip 30 puncte
helliphelliphelliphelliphelliphelliphelliphellip 15 puncte
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 8 p
(D)
(Frsquo)
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p
+ K2SO4 + Cr2(SO4)3 + 7 H2O
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
helliphelliphelliphelliphelliphelliphelliphelliphellip 1 p
helliphelliphelliphelliphelliphelliphelliphellip 5 puncte
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 5 p
C
CH3
CH2OH
CHCCH3
CH3 O
O-Na+
O
H
C CH2
OH CH3
C
+ CHO
8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem
httpslidepdfcomreaderfull2015-chimie-judeteana-clasa-a-xia-subiectebarem 77
C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
a Formula moleculară C3H8O3 For
b Modelarea ecuaţiilor reacţiilor ch
c VC3H6(1 atm 27degC) = 30769 m3 helliphellip
NOTĂ Orice altă variantă corect
Barem elaborat de Ignat Iuliana pr
Str General B
DIR
IcircNVĂȚĂM
CH2
CH
CH2
OH
OH
OH
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
mula structurală helliphelliphelliphelliphelliphelliphellip
imice şi condițiile acestora de obţinere a polialco
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
ă de rezolvare se va lua icircn considerare
fesor la Liceul Pedagogic bdquoDP Perpessiciusrdquo
erthelot nr 28-30 Sector 1 010168 Bucureşti
Tel +40 (0)21 40 63 00
wwweduro
ECȚIAGENERALĂ
NT PREUNIVERSITAR
helliphelliphelliphelliphelliphelliphelliphellip 10 puncte
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p
olului de la propenă helliphellip 4 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
Br ăila
8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem
httpslidepdfcomreaderfull2015-chimie-judeteana-clasa-a-xia-subiectebarem 77
C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
a Formula moleculară C3H8O3 For
b Modelarea ecuaţiilor reacţiilor ch
c VC3H6(1 atm 27degC) = 30769 m3 helliphellip
NOTĂ Orice altă variantă corect
Barem elaborat de Ignat Iuliana pr
Str General B
DIR
IcircNVĂȚĂM
CH2
CH
CH2
OH
OH
OH
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
mula structurală helliphelliphelliphelliphelliphelliphellip
imice şi condițiile acestora de obţinere a polialco
helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip
ă de rezolvare se va lua icircn considerare
fesor la Liceul Pedagogic bdquoDP Perpessiciusrdquo
erthelot nr 28-30 Sector 1 010168 Bucureşti
Tel +40 (0)21 40 63 00
wwweduro
ECȚIAGENERALĂ
NT PREUNIVERSITAR
helliphelliphelliphelliphelliphelliphelliphellip 10 puncte
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p
olului de la propenă helliphellip 4 p
helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p
Br ăila
top related