2015 chimie judeteana clasa a xia subiectebarem

7
8/19/2019 2015 Chimie Judeteana Clasa a Xia Subiectebarem http://slidepdf.com/reader/full/2015-chimie-judeteana-clasa-a-xia-subiectebarem 1/7  CCl Pd/Pb 2+  OL Subiectul I ……………………… A. ………………………………… Se dau formulele de structură pentru I. Linalool din ulei de lavandă IV. Amfetamina a. Precizaţi denumirea conform IUP b. Scrieţi formulele structurale ale st c. Substanţele IV şi V sunt insolubi numai în unul din cazuri se păst deosebirea dintre aceste substanţe. B. ………………………………… 1. Scrieţi formulele de structură pen a. trans–3–hexenă + Br 2  b. cis–2–butenă + [O] + H 2 O c. trans–2, 3–dimetil–3–hexen  d. 2–butină + H 2  O e. ciclopentenă + C 6 H 5 –C O–  2. Degradarea Hofmann a bazelor ecuaţiile reacţiilor chimice de obţin Str. General B DIR ÎNVĂȚĂM  KMnO 4  /HO  ‾  Ni Clasa a XI-a  MPIADA DE CHIMIE – etapa jude  ţ eană 21 februarie 2015 ………………………………………………… ……………………………………………… compuşii: II. Citral din ulei de lămâie III. Benzedrina) V.  AC pentru I, II, III şi IV; ereoizomerilor corespunzători compuşilor II şi II  le în apă, dar solubile în soluţie de HCl 5%. Du ează solubilitatea în soluţie de HCl 5%. Ex ………………………………………………… ru stereoizomerii produşilor următoarelor reacţii ă + H 2  O–H cuaternare de amoniu are loc la temperaturi re a etenei prin degradări Hofmann ale metil–etil  erthelot nr. 28-30, Sector 1, 010168, Bucureşti Tel: +40 (0)21 40 63 00 www.edu.ro ECȚIA GENERALĂ NT PREUNIVERSITAR …………………. 20 puncte …………………… 12 puncte Efedrina din planta de cârcel Tetracaina I; ă reacţia cu anhidrida acetică, licaţi atât asemănarea, cât şi …………………… 8 puncte : ai mari de 100°C. Modelaţi –butil–aminei.

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Page 1: 2015 Chimie Judeteana Clasa a Xia Subiectebarem

8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem

httpslidepdfcomreaderfull2015-chimie-judeteana-clasa-a-xia-subiectebarem 17

CCl

PdPb2+

OL

Subiectul I helliphelliphelliphelliphelliphelliphelliphelliphellip

A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

Se dau formulele de structură pentru

I Linalool din ulei delavandă

IV Amfetamina

a Precizaţi denumirea conform IUPb Scrieţi formulele structurale ale stc Substanţele IV şi V sunt insolubinumai icircn unul din cazuri se păstdeosebirea dintre aceste substanţe

B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

1 Scrieţi formulele de structură pen

a transndash3ndashhexenă + Br2

b cisndash2ndashbutenă + [O] + H2O

c transndash2 3ndashdimetilndash3ndashhexen

d 2ndashbutină + H2

Oe ciclopentenă + C6H5ndashC

Ondash 2 Degradarea Hofmann a bazelorecuaţiile reacţiilor chimice de obţin

Str General B

DIR

IcircNVĂȚĂM

KMnO4 HO oline

Ni

Clasa a XI-a

MPIADA DE CHIMIE ndash etapa jude ţ eană

21 februarie 2015

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

compuşii

II Citral din uleide lămacircie

III

Benzedrina) V

AC pentru I II III şi IVereoizomerilor corespunzători compuşilor II şi II

le icircn apă dar solubile icircn soluţie de HCl 5 Duează solubilitatea icircn soluţie de HCl 5 Ex

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

ru stereoizomerii produşilor următoarelor reacţii

ă + H2

OndashH

cuaternare de amoniu are loc la temperaturire a etenei prin degradări Hofmann ale metilndashetil

erthelot nr 28-30 Sector 1 010168 Bucureşti

Tel +40 (0)21 40 63 00

wwweduro

ECȚIAGENERALĂ

NT PREUNIVERSITAR

helliphelliphelliphelliphelliphelliphellip 20 puncte

helliphelliphelliphelliphelliphelliphelliphellip 12 puncte

Efedrina din plantade cacircrcel

Tetracaina

Iă reacţia cu anhidrida aceticălicaţi atacirct asemănarea cacirct şi

helliphelliphelliphelliphelliphelliphelliphellip 8 puncte

ai mari de 100degC Modelaţindashbutilndashaminei

8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem

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ndash H2O230degC

+ 2HA

+ (CH3)

ndash CH3O

Subiectul II helliphelliphelliphelliphelliphelliphelliphelliphellip

A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip1 bdquoParabeniirdquo sunt compuşi ordezinfectanţi şi arome icircn industria

următoarei schemeC6H5ndashOH + KOH A

2 B C + C6H5ndashOH + CO2

C acid pndashhidroxibenzoic

Se cerea Scrieţi ecuaţiile reacţiilor reprezeb Denumiţi conform IUPAC substac Pentru cei doi acizi izomeri din159degC precum și constantele de acid Icircn Australia se interzice folosireainterdicție2 a Scrieți formulele structuralepndashmetoxifenoxid

b Acidul pndashhidroxibenzoic estNaHCO3

HOndashC6

oline OndashC

Ordonați cele patru specii acide icircn oB helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellipUn amestec de acid oxalic și acid foun amestec gazos cu volumul de 06Se cerea Calculați raportul molar al celor db O probă H2C2O4middot2H2O cu masaacidului cristalizat (impuritățile nu r

Subiectul III helliphelliphelliphelliphelliphelliphelliphellip

A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

1 Etanolaminele sunt substanțe foletilenoxid Se introduc icircn soluție apcu o cantitate dublă de etilenoxid gsepară 915 kg monoetanolamina 6Să se calculezea Compoziția icircn procente molare ab Randamentul de transformare a a2 Scrieți ecuațiile reacțiilor posibilde reacție

B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellipIcircntr-un vas cu dop rodat se cacircntăre

brom 005M Se icircnchide vasul și seprin reacția cu excesul de brom colamidon pacircnă la decolorare Calculcondițiile date tiosulfatul de sodiu s

p =

ndash 2KA

Str General B

DIR

IcircNVĂȚĂM

CO2 H2SO4

ndashKHSO4

ROH(H2SO4)

ndashH2O

OSO3

O3H

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellipanici derivaţi de la acidul parahidroxibenzoifarmaceutică cosmetică şi alimentară Aceste s

B acid salicilic

parabeni

E (aromă de anason)

tate icircn schemănţa (E) şi parabenii conservanţi preparaţi cu CH

schemă atribuiți valorile potrivite ale puncteloitate Ka = 105middot10-4 și Ka = 2610-5 Justificați al

parabenilor icircn scopurile enumerate icircn text Form

ale următorilor anioni icircn ordinea creșterii bazi

un acid diprotic pentru care se dau ecuațiile

H4ndashCOOH + HCO3 oline HOndashC6H4ndashCOO oline + H2CH4ndashCOO oline + HCO3 oline HOndashC6H4ndashCOO oline + CO3

2

rdinea descrescătoare a acidității lorhelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

rmic obținut din greșeală se tratează cu 10 g sol72 L (cn) și cu densitatea de 1464 gL (cn)

oi acizi icircn amestece 0130 g este titrată cu 20 mL soluție de KM

eacționează cu KMnO4)

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

site icircn cosmetică industria textilă și de pielărieasă 246 m3 amoniac la temperatura de 27degC șiazos Se obține un amestec al celor trei etanola0 kg dietanolamina și 298 kg trietanolamina

mestecului final de aminoalcoolioniacului și conversia icircn dietanolamină icircntre monoetanolamină (colina) și acid acetic

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellipsc 002 g fenol brut Se adaugă 10 mL acid ac

lasă la icircntuneric 20 minute apoi se adaugă 10orează soluția icircn brun şi se titrează cu soluție daţi puritatea probei de fenol dacă s-au consutransformă icircn Na2S4O6

atm 125degC

erthelot nr 28-30 Sector 1 010168 Bucureşti

Tel +40 (0)21 40 63 00

wwweduro

ECȚIAGENERALĂ

NT PREUNIVERSITAR

helliphelliphelliphelliphelliphelliphelliphellip 25 puncte

helliphelliphelliphelliphelliphelliphelliphellip 15 punctec utilizaţi drept conservanţibstanţe se pot obţine conform

ndash OH respectiv C7H15 ndash OHde topire 213degC și respectiv

egerealați o motivație pentru această

cității fenoxid pndashnitrofenoxid

reacțiilor icircn soluție apoasă de

3 oline

helliphelliphelliphelliphelliphelliphelliphellip 10 puncteuție de H2SO4 95 și se obține

O4 002M Calculați puritatea

helliphelliphelliphelliphelliphelliphellip 25 puncte

helliphelliphelliphelliphelliphelliphelliphellip 10 puncte

care se prepară din amoniac șipresiunea de 10 atm icircmpreună ine din care după distilare se

precizacircnd tipul fiecărui produs

helliphelliphelliphelliphelliphelliphelliphellip 8 punctetic glacial și 25mL soluție de

L soluție KI 1M Iodul formatNa2S2O3 01M icircn prezență deat 13 mL soluție Na2S2O3 Icircn

8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem

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CH3MgBr (exces) H2O

HO ndash

K2Cr2O7 H+

HCl

C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

Se consideră produsul carbonilicpropionică (A) și acetona (B)

Se cerea Să se indice o schemă de reacțisimultan ambele substanțe (A) și (Bb Să se indice o schemă de reacțiiuna icircn alta

Subiectul IV helliphelliphelliphelliphelliphelliphelliphellip

A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

Substanța (A) are formula moleculcristalizat cu 24 dinitrofenilhidrazide la substanţa (A) se pot scrie ecua

A B D E + NaCl

acetonă + butanal F

F E + H2O

Compusul (B) are formula molec(DNFH) Compusul (E) colorează icirca Scrieți ecuațiile reacțiilor din schb Denumiți conform IUPAC substa

c La dozarea unei soluții a substandin proba de analizat

B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

La echilibrul unei reacţii chimiceCH3COOH 13 moli C2H5OH 23respectivă este 4 Să se calculezeechilibru se mai adaugă 1 mol C2H5

C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

Prin tratarea unui polialcool saturatreprezintă 13695 comparativ cu p

Se cerea Formula moleculară şi structurală b Scrierea ecuaţiilor reacţiilor chiraport cu aerul este 145c Volumul hidrocarburii măsurat lglobal al reacţiilor este 80

Se dau- Mase atomice H - 1 C - 12 N -- Volumul molar V = 224 Lmol- Masa moleculară a aerului microaer =- Constanta universală a gazelor

NOTĂ Timp de lucru 3 ore

Subiecte propuse de Ignat Iuliana

Str General B

DIR

IcircNVĂȚĂM

K2Cr2O7 H+ I2 NaOH

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

u formula moleculară C3H6O sub forma celo

i și condițiile acestora prin care pornind de la

și condițiile lor prin care cele două substanțe (A

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

ră C6H10O2 este neutră față de indicatorii acido a (DNFH) reacționează cu reactiv Tollens și d

iile reacțiilor chimice conform schemei de mai j

C D + CHI3

+ Frsquo

lară C8H18O2 reacționează rapid cu reactivroșu soluția de metilorange și reacționează rapi

mă și cele ale substanței (A) cu DNFH și (A) cunțele notate cu (A) (B) (C) şi (E)

ei (B) se consumă 15mL soluție K2Cr2O7 02M

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

icircntre etanol şi acid acetic compoziţia amestecmoli CH3COOC2H5 şi 23 moli H2O Constan

conversia totală de transformare a acidului acH la volum constant

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

cu anhidridă acidă icircn exces masa moleculară olialcoolul

a polialcooluluiice de obţinere a polialcoolului pornind de la hi

a 1 atm şi 27degC necesar obţinerii a 920 kg po

14 O - 16 Na - 23 S - 32 Cl - 355 K - 39 Cr

2896 gmol= 0082 atmmiddotdm3 molmiddotK

rofesor la Liceul Pedagogic bdquoDP Perpessicius

erthelot nr 28-30 Sector 1 010168 Bucureşti

Tel +40 (0)21 40 63 00

wwweduro

ECȚIAGENERALĂ

NT PREUNIVERSITAR

helliphelliphelliphelliphelliphelliphelliphellip 7 puncte

r doi izomeri ai săi aldehida

un compus unic să se obțină

) și (B) să se poată transforma

helliphelliphelliphelliphelliphelliphellip 30 puncte

helliphelliphelliphelliphelliphelliphelliphellip 15 puncte

- bazici formează un compusreacția iodoformului Pornind

os

ucas dar nu reacționează cucu reactiv Lucas

reactiv Tollens

Calculați masa substanței (B)

helliphelliphelliphelliphelliphelliphelliphellip 5 puncte

lui este următoarea 13 molita de echilibru la temperaturaetic dacă peste amestecul de

helliphelliphelliphelliphelliphelliphelliphellip 10 puncte

reşte cu 126 Această creştere

drocarbura a cărei densitate icircn

lialcool ştiind că randamentul

- 52 Mn - 55 Br - 80 I - 127

Br ăila

8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem

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ndash H2O

230degC

+ 2HA

+ndash

C

O-

COO-K+

O-K+

OL

BA

Subiectul I helliphelliphelliphelliphelliphelliphelliphelliphellipA helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellipa 4 denumiri conform IUPAC times 1p

b Compusul II prezintă doi diastere

Compusul III prezintă 2 atomi de

2 perechi de

c Explicaţie helliphelliphelliphelliphelliphelliphelliphelliphellip

Asemănarea ndash caracterul ba

Deosebirea ndash Amfetamina (

HCl 5 Tetracaina după acilare

rămacircne solubilă icircn soluţia de HCl 5

B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip1 helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

a mezondash3 4ndashdibromhexan (mezofo

b cisndash2 3ndashbutandiol (mezoformă)

c (plusmn)ndash2 3ndashdimetilhexan (amestec r

d cisndash2ndashbutenă

e (plusmn)transndash1 2ndashciclopentandiol (a

2 Modelarea ecuaţiilor reacţiilor ch

se ca produşi finali de reacţie CH2=

Subiectul II helliphelliphelliphelliphelliphelliphelliphelliphellip

A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

1 a helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

C6H5ndashOH + KOH C6H5ndashO

2

acid pndashhidroxindash 2KA

OH

COO-K+

Str General B

DIR

IcircNVĂȚĂM

+ CO2 H2SO4

ndashKHSO

ROH(H2SO4)

ndashH2O

(CH3)2OSO3 CH3OSO3H

OHO-K+

+

COOR

OH

COOH

OCH3

MPIADA DE CHIMIE ndash etapa jude ţ eană

21 februarie 2015

EM DE EVALUARE ndash CLASA A XI-A

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

oizomeri Z (cis) E (trans) 2 structuri times 1p helliphellip

carbon asimetrici

nantiomeri (eritro plusmn treo plusmn) 4 structuri times 05p

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

zic demonstrat prin scrierea ecuaţiilor reacţiilor c

Benzedrina) după acilare pierde caracterul bazi

avacircnd icircn structura sa grefată şi o grupare amin

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

rmă)

cemic)

estec racemic)

imice degradări Hofmann (metilare urmată de icircn

CH2 şi (CH3)3N helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

oline K+

+ + CO2

benzoic

p = 6 atm 125degC

OH

COO-K+

erthelot nr 28-30 Sector 1 010168 Bucureşti

Tel +40 (0)21 40 63 00

wwweduro

ECȚIAGENERALĂ

NT PREUNIVERSITAR

4

helliphelliphelliphelliphelliphelliphellip 20 punctehelliphelliphelliphelliphelliphelliphelliphellip 12 punctehelliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p

himice

şi este insolubilă icircn soluţia de

o terţiară care nu se acilează

helliphelliphelliphelliphelliphelliphelliphellip 8 punctehelliphelliphelliphelliphelliphelliphelliphelliphelliphellip 5 p

călzire cu Ag(OH)) obţinacircndu-

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 3 p

helliphelliphelliphelliphelliphelliphelliphellip 25 puncte

helliphelliphelliphelliphelliphelliphelliphellip 15 puncte

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 7 p

OH

COOH

8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem

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OH

COOH

COOH

OH

NO2

O-O-

b (E) acid pndashmetoxibenzoic helliphellip

parahidroxibenzoat de metil helliphelliphellip

parahidroxibenzoat de nndashheptil hellip

c

punct d

punct de to

Ka

Justificare

d Parabenii au potenţial efect cance

2 a helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

lt

b HOndashC6H4ndashCOOH gt H2CO3 gt HC

B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellipa HCOOH rarr CO + H2O hellip

H2C2O4 rarr CO + CO2 + H2

νamestgaze = 003 moli mgaze

b 5 H2C2O4 + 2 KMnO4 + 3 H2SO4

νKMnO4 = 00004 moli m H2C

Subiectul III helliphelliphelliphelliphelliphelliphelliphellip

A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip1 a 3 ecuaţii chimice times 1p helliphelliphellip

Compoziţia icircn procente molare a a

1579 (monoetanolamina)

b η = 95 c= 60 helliphelliphelliphelliphelliphellip

2 4 ecuaţii chimice times 1p helliphelliphelliphellip

B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

C6H5ndashOH + 3Br2 rarr C6H2Br3ndashOH +

Br2 + 2KI rarr 2KBr + I2 helliphelliphelliphellip

I2 + 2Na2S2O3 rarr Na2S4O6 + 2NaI

νNa2S2O3 = 13middot10

-4

moli helliphelliphelliphelliphellip νI2 = νBr2(exces) = 65middot10-4

moli helliphellip

νBr2 icircn reacţia cu fenolul = 6middot10-4

moli helliphellip

p = 94 helliphelliphelliphelliphelliphelliphelliphelliphelliphellip

Str General B

DIR

IcircNVĂȚĂM

O-

CH3O

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

e topire = 159degC

a = 105middot10-4

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

ire = 213degC

26middot10-4

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

rigen datorită nucleului benzenic helliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

lt

O3macr gt HOndashC6H4ndashCOO

macr helliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

09838 g νHCOOH νH2C2O4 = 43 helliphelliphelliphelliphellip

rarr 10 CO2 + K2SO4 + 2MnSO4 + 8 H2Ohelliphelliphellip

2O4middot2H2O = 0126 g p = 96923 helliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

estecului final 6316 (dietanolamina) 2105 (trietanolami

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

3 HBr helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

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helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphellip 05 p

helliphelliphelliphelliphelliphelliphelliphelliphellip 05 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p helliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphellip 10 punctehelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p

helliphelliphelliphelliphelliphelliphellip 25 puncte

helliphelliphelliphelliphelliphelliphelliphellip 10 punctehelliphelliphelliphelliphelliphelliphelliphelliphelliphellip 3 p

a) helliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p

helliphelliphelliphelliphelliphelliphelliphellip 8 puncte

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 phelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

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CH3

CH2

CH

OH

CHCCH3

CH3

OH

CH3

C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

a Modelarea ecuaţiilor reacţiilor

ozonizare urmată de hidroliză helliphellip

b Ararr helliprarr B helliphelliphelliphelliphellip

Brarr helliprarr A helliphelliphelliphelliphellip

Subiectul IV helliphelliphelliphelliphelliphelliphelliphellip

A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

a 8 ecuaţii chimice times 1p helliphelliphelliphellip

(A) (

(E)

b 4 denumiri conform IUPAC times 1p

(A) 2ndashetilndash3ndashoxondashbutanal

(B) 3ndashetilndash2 metilndash2 4ndashpentandiol

(C) 3ndashetilndash4 metilndash4ndashhidroxindash2ndashpe

(E) acid 2ndashetilndash3ndashmetilndash3ndashhidroxib

c

3 + K

νK2Cr2O7 = 0003 moli νB= 0009 mo

B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

Ctotal = 1

3

∙100

Ctotal = 8447 helliphelliphelliphelliphelliphelliphelliphellip

CH3 C CH

O

CHO

CH2

CH3

OH

CCH3

CH

C

O

CH3

CH2OH

CHCCH3

CH3

OH CH3

CH3 C CH CH2 C

CH3

Str General B

DIR

IcircNVĂȚĂM

C

CH3

CH3 C CH

OH CH2

CH3

O

C

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

himice şi condițiile acestora Se poate porni

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphellip

(A)

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

B) (C)

(F)

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

tanonă

utanoic

2Cr2O7 + 4H2SO4 3

hellip

l mB = 1314 g helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

CH3

CH2

CHCH

OH

CH3 CH

CH3

CH3 C CH

OH CH2

CH3

O

C

C

CH3

CH2OH

CHC

CH3

O

H CH2CH3 CH2

3 CH2CH3

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O

CH3CCH3

H3

helliphelliphelliphelliphelliphelliphelliphellip 7 puncte

de la 2ndashmetilndash2ndashpentenă prin

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 3 p

(B)

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

helliphelliphelliphelliphelliphelliphellip 30 puncte

helliphelliphelliphelliphelliphelliphelliphellip 15 puncte

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 8 p

(D)

(Frsquo)

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p

+ K2SO4 + Cr2(SO4)3 + 7 H2O

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

helliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphellip 5 puncte

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 5 p

C

CH3

CH2OH

CHCCH3

CH3 O

O-Na+

O

H

C CH2

OH CH3

C

+ CHO

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C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

a Formula moleculară C3H8O3 For

b Modelarea ecuaţiilor reacţiilor ch

c VC3H6(1 atm 27degC) = 30769 m3 helliphellip

NOTĂ Orice altă variantă corect

Barem elaborat de Ignat Iuliana pr

Str General B

DIR

IcircNVĂȚĂM

CH2

CH

CH2

OH

OH

OH

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

mula structurală helliphelliphelliphelliphelliphelliphellip

imice şi condițiile acestora de obţinere a polialco

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

ă de rezolvare se va lua icircn considerare

fesor la Liceul Pedagogic bdquoDP Perpessiciusrdquo

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helliphelliphelliphelliphelliphelliphelliphellip 10 puncte

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p

olului de la propenă helliphellip 4 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

Br ăila

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ndash H2O230degC

+ 2HA

+ (CH3)

ndash CH3O

Subiectul II helliphelliphelliphelliphelliphelliphelliphelliphellip

A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip1 bdquoParabeniirdquo sunt compuşi ordezinfectanţi şi arome icircn industria

următoarei schemeC6H5ndashOH + KOH A

2 B C + C6H5ndashOH + CO2

C acid pndashhidroxibenzoic

Se cerea Scrieţi ecuaţiile reacţiilor reprezeb Denumiţi conform IUPAC substac Pentru cei doi acizi izomeri din159degC precum și constantele de acid Icircn Australia se interzice folosireainterdicție2 a Scrieți formulele structuralepndashmetoxifenoxid

b Acidul pndashhidroxibenzoic estNaHCO3

HOndashC6

oline OndashC

Ordonați cele patru specii acide icircn oB helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellipUn amestec de acid oxalic și acid foun amestec gazos cu volumul de 06Se cerea Calculați raportul molar al celor db O probă H2C2O4middot2H2O cu masaacidului cristalizat (impuritățile nu r

Subiectul III helliphelliphelliphelliphelliphelliphelliphellip

A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

1 Etanolaminele sunt substanțe foletilenoxid Se introduc icircn soluție apcu o cantitate dublă de etilenoxid gsepară 915 kg monoetanolamina 6Să se calculezea Compoziția icircn procente molare ab Randamentul de transformare a a2 Scrieți ecuațiile reacțiilor posibilde reacție

B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellipIcircntr-un vas cu dop rodat se cacircntăre

brom 005M Se icircnchide vasul și seprin reacția cu excesul de brom colamidon pacircnă la decolorare Calculcondițiile date tiosulfatul de sodiu s

p =

ndash 2KA

Str General B

DIR

IcircNVĂȚĂM

CO2 H2SO4

ndashKHSO4

ROH(H2SO4)

ndashH2O

OSO3

O3H

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellipanici derivaţi de la acidul parahidroxibenzoifarmaceutică cosmetică şi alimentară Aceste s

B acid salicilic

parabeni

E (aromă de anason)

tate icircn schemănţa (E) şi parabenii conservanţi preparaţi cu CH

schemă atribuiți valorile potrivite ale puncteloitate Ka = 105middot10-4 și Ka = 2610-5 Justificați al

parabenilor icircn scopurile enumerate icircn text Form

ale următorilor anioni icircn ordinea creșterii bazi

un acid diprotic pentru care se dau ecuațiile

H4ndashCOOH + HCO3 oline HOndashC6H4ndashCOO oline + H2CH4ndashCOO oline + HCO3 oline HOndashC6H4ndashCOO oline + CO3

2

rdinea descrescătoare a acidității lorhelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

rmic obținut din greșeală se tratează cu 10 g sol72 L (cn) și cu densitatea de 1464 gL (cn)

oi acizi icircn amestece 0130 g este titrată cu 20 mL soluție de KM

eacționează cu KMnO4)

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

site icircn cosmetică industria textilă și de pielărieasă 246 m3 amoniac la temperatura de 27degC șiazos Se obține un amestec al celor trei etanola0 kg dietanolamina și 298 kg trietanolamina

mestecului final de aminoalcoolioniacului și conversia icircn dietanolamină icircntre monoetanolamină (colina) și acid acetic

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellipsc 002 g fenol brut Se adaugă 10 mL acid ac

lasă la icircntuneric 20 minute apoi se adaugă 10orează soluția icircn brun şi se titrează cu soluție daţi puritatea probei de fenol dacă s-au consutransformă icircn Na2S4O6

atm 125degC

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helliphelliphelliphelliphelliphelliphelliphellip 25 puncte

helliphelliphelliphelliphelliphelliphelliphellip 15 punctec utilizaţi drept conservanţibstanţe se pot obţine conform

ndash OH respectiv C7H15 ndash OHde topire 213degC și respectiv

egerealați o motivație pentru această

cității fenoxid pndashnitrofenoxid

reacțiilor icircn soluție apoasă de

3 oline

helliphelliphelliphelliphelliphelliphelliphellip 10 puncteuție de H2SO4 95 și se obține

O4 002M Calculați puritatea

helliphelliphelliphelliphelliphelliphellip 25 puncte

helliphelliphelliphelliphelliphelliphelliphellip 10 puncte

care se prepară din amoniac șipresiunea de 10 atm icircmpreună ine din care după distilare se

precizacircnd tipul fiecărui produs

helliphelliphelliphelliphelliphelliphelliphellip 8 punctetic glacial și 25mL soluție de

L soluție KI 1M Iodul formatNa2S2O3 01M icircn prezență deat 13 mL soluție Na2S2O3 Icircn

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CH3MgBr (exces) H2O

HO ndash

K2Cr2O7 H+

HCl

C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

Se consideră produsul carbonilicpropionică (A) și acetona (B)

Se cerea Să se indice o schemă de reacțisimultan ambele substanțe (A) și (Bb Să se indice o schemă de reacțiiuna icircn alta

Subiectul IV helliphelliphelliphelliphelliphelliphelliphellip

A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

Substanța (A) are formula moleculcristalizat cu 24 dinitrofenilhidrazide la substanţa (A) se pot scrie ecua

A B D E + NaCl

acetonă + butanal F

F E + H2O

Compusul (B) are formula molec(DNFH) Compusul (E) colorează icirca Scrieți ecuațiile reacțiilor din schb Denumiți conform IUPAC substa

c La dozarea unei soluții a substandin proba de analizat

B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

La echilibrul unei reacţii chimiceCH3COOH 13 moli C2H5OH 23respectivă este 4 Să se calculezeechilibru se mai adaugă 1 mol C2H5

C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

Prin tratarea unui polialcool saturatreprezintă 13695 comparativ cu p

Se cerea Formula moleculară şi structurală b Scrierea ecuaţiilor reacţiilor chiraport cu aerul este 145c Volumul hidrocarburii măsurat lglobal al reacţiilor este 80

Se dau- Mase atomice H - 1 C - 12 N -- Volumul molar V = 224 Lmol- Masa moleculară a aerului microaer =- Constanta universală a gazelor

NOTĂ Timp de lucru 3 ore

Subiecte propuse de Ignat Iuliana

Str General B

DIR

IcircNVĂȚĂM

K2Cr2O7 H+ I2 NaOH

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

u formula moleculară C3H6O sub forma celo

i și condițiile acestora prin care pornind de la

și condițiile lor prin care cele două substanțe (A

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

ră C6H10O2 este neutră față de indicatorii acido a (DNFH) reacționează cu reactiv Tollens și d

iile reacțiilor chimice conform schemei de mai j

C D + CHI3

+ Frsquo

lară C8H18O2 reacționează rapid cu reactivroșu soluția de metilorange și reacționează rapi

mă și cele ale substanței (A) cu DNFH și (A) cunțele notate cu (A) (B) (C) şi (E)

ei (B) se consumă 15mL soluție K2Cr2O7 02M

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

icircntre etanol şi acid acetic compoziţia amestecmoli CH3COOC2H5 şi 23 moli H2O Constan

conversia totală de transformare a acidului acH la volum constant

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

cu anhidridă acidă icircn exces masa moleculară olialcoolul

a polialcooluluiice de obţinere a polialcoolului pornind de la hi

a 1 atm şi 27degC necesar obţinerii a 920 kg po

14 O - 16 Na - 23 S - 32 Cl - 355 K - 39 Cr

2896 gmol= 0082 atmmiddotdm3 molmiddotK

rofesor la Liceul Pedagogic bdquoDP Perpessicius

erthelot nr 28-30 Sector 1 010168 Bucureşti

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ECȚIAGENERALĂ

NT PREUNIVERSITAR

helliphelliphelliphelliphelliphelliphelliphellip 7 puncte

r doi izomeri ai săi aldehida

un compus unic să se obțină

) și (B) să se poată transforma

helliphelliphelliphelliphelliphelliphellip 30 puncte

helliphelliphelliphelliphelliphelliphelliphellip 15 puncte

- bazici formează un compusreacția iodoformului Pornind

os

ucas dar nu reacționează cucu reactiv Lucas

reactiv Tollens

Calculați masa substanței (B)

helliphelliphelliphelliphelliphelliphelliphellip 5 puncte

lui este următoarea 13 molita de echilibru la temperaturaetic dacă peste amestecul de

helliphelliphelliphelliphelliphelliphelliphellip 10 puncte

reşte cu 126 Această creştere

drocarbura a cărei densitate icircn

lialcool ştiind că randamentul

- 52 Mn - 55 Br - 80 I - 127

Br ăila

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ndash H2O

230degC

+ 2HA

+ndash

C

O-

COO-K+

O-K+

OL

BA

Subiectul I helliphelliphelliphelliphelliphelliphelliphelliphellipA helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellipa 4 denumiri conform IUPAC times 1p

b Compusul II prezintă doi diastere

Compusul III prezintă 2 atomi de

2 perechi de

c Explicaţie helliphelliphelliphelliphelliphelliphelliphelliphellip

Asemănarea ndash caracterul ba

Deosebirea ndash Amfetamina (

HCl 5 Tetracaina după acilare

rămacircne solubilă icircn soluţia de HCl 5

B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip1 helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

a mezondash3 4ndashdibromhexan (mezofo

b cisndash2 3ndashbutandiol (mezoformă)

c (plusmn)ndash2 3ndashdimetilhexan (amestec r

d cisndash2ndashbutenă

e (plusmn)transndash1 2ndashciclopentandiol (a

2 Modelarea ecuaţiilor reacţiilor ch

se ca produşi finali de reacţie CH2=

Subiectul II helliphelliphelliphelliphelliphelliphelliphelliphellip

A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

1 a helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

C6H5ndashOH + KOH C6H5ndashO

2

acid pndashhidroxindash 2KA

OH

COO-K+

Str General B

DIR

IcircNVĂȚĂM

+ CO2 H2SO4

ndashKHSO

ROH(H2SO4)

ndashH2O

(CH3)2OSO3 CH3OSO3H

OHO-K+

+

COOR

OH

COOH

OCH3

MPIADA DE CHIMIE ndash etapa jude ţ eană

21 februarie 2015

EM DE EVALUARE ndash CLASA A XI-A

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

oizomeri Z (cis) E (trans) 2 structuri times 1p helliphellip

carbon asimetrici

nantiomeri (eritro plusmn treo plusmn) 4 structuri times 05p

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

zic demonstrat prin scrierea ecuaţiilor reacţiilor c

Benzedrina) după acilare pierde caracterul bazi

avacircnd icircn structura sa grefată şi o grupare amin

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

rmă)

cemic)

estec racemic)

imice degradări Hofmann (metilare urmată de icircn

CH2 şi (CH3)3N helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

oline K+

+ + CO2

benzoic

p = 6 atm 125degC

OH

COO-K+

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4

helliphelliphelliphelliphelliphelliphellip 20 punctehelliphelliphelliphelliphelliphelliphelliphellip 12 punctehelliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p

himice

şi este insolubilă icircn soluţia de

o terţiară care nu se acilează

helliphelliphelliphelliphelliphelliphelliphellip 8 punctehelliphelliphelliphelliphelliphelliphelliphelliphelliphellip 5 p

călzire cu Ag(OH)) obţinacircndu-

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 3 p

helliphelliphelliphelliphelliphelliphelliphellip 25 puncte

helliphelliphelliphelliphelliphelliphelliphellip 15 puncte

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 7 p

OH

COOH

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OH

COOH

COOH

OH

NO2

O-O-

b (E) acid pndashmetoxibenzoic helliphellip

parahidroxibenzoat de metil helliphelliphellip

parahidroxibenzoat de nndashheptil hellip

c

punct d

punct de to

Ka

Justificare

d Parabenii au potenţial efect cance

2 a helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

lt

b HOndashC6H4ndashCOOH gt H2CO3 gt HC

B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellipa HCOOH rarr CO + H2O hellip

H2C2O4 rarr CO + CO2 + H2

νamestgaze = 003 moli mgaze

b 5 H2C2O4 + 2 KMnO4 + 3 H2SO4

νKMnO4 = 00004 moli m H2C

Subiectul III helliphelliphelliphelliphelliphelliphelliphellip

A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip1 a 3 ecuaţii chimice times 1p helliphelliphellip

Compoziţia icircn procente molare a a

1579 (monoetanolamina)

b η = 95 c= 60 helliphelliphelliphelliphelliphellip

2 4 ecuaţii chimice times 1p helliphelliphelliphellip

B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

C6H5ndashOH + 3Br2 rarr C6H2Br3ndashOH +

Br2 + 2KI rarr 2KBr + I2 helliphelliphelliphellip

I2 + 2Na2S2O3 rarr Na2S4O6 + 2NaI

νNa2S2O3 = 13middot10

-4

moli helliphelliphelliphelliphellip νI2 = νBr2(exces) = 65middot10-4

moli helliphellip

νBr2 icircn reacţia cu fenolul = 6middot10-4

moli helliphellip

p = 94 helliphelliphelliphelliphelliphelliphelliphelliphelliphellip

Str General B

DIR

IcircNVĂȚĂM

O-

CH3O

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

e topire = 159degC

a = 105middot10-4

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

ire = 213degC

26middot10-4

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

rigen datorită nucleului benzenic helliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

lt

O3macr gt HOndashC6H4ndashCOO

macr helliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

09838 g νHCOOH νH2C2O4 = 43 helliphelliphelliphelliphellip

rarr 10 CO2 + K2SO4 + 2MnSO4 + 8 H2Ohelliphelliphellip

2O4middot2H2O = 0126 g p = 96923 helliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

estecului final 6316 (dietanolamina) 2105 (trietanolami

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

3 HBr helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

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helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphellip 05 p

helliphelliphelliphelliphelliphelliphelliphelliphellip 05 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p helliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphellip 10 punctehelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p

helliphelliphelliphelliphelliphelliphellip 25 puncte

helliphelliphelliphelliphelliphelliphelliphellip 10 punctehelliphelliphelliphelliphelliphelliphelliphelliphelliphellip 3 p

a) helliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p

helliphelliphelliphelliphelliphelliphelliphellip 8 puncte

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 phelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

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CH3

CH2

CH

OH

CHCCH3

CH3

OH

CH3

C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

a Modelarea ecuaţiilor reacţiilor

ozonizare urmată de hidroliză helliphellip

b Ararr helliprarr B helliphelliphelliphelliphellip

Brarr helliprarr A helliphelliphelliphelliphellip

Subiectul IV helliphelliphelliphelliphelliphelliphelliphellip

A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

a 8 ecuaţii chimice times 1p helliphelliphelliphellip

(A) (

(E)

b 4 denumiri conform IUPAC times 1p

(A) 2ndashetilndash3ndashoxondashbutanal

(B) 3ndashetilndash2 metilndash2 4ndashpentandiol

(C) 3ndashetilndash4 metilndash4ndashhidroxindash2ndashpe

(E) acid 2ndashetilndash3ndashmetilndash3ndashhidroxib

c

3 + K

νK2Cr2O7 = 0003 moli νB= 0009 mo

B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

Ctotal = 1

3

∙100

Ctotal = 8447 helliphelliphelliphelliphelliphelliphelliphellip

CH3 C CH

O

CHO

CH2

CH3

OH

CCH3

CH

C

O

CH3

CH2OH

CHCCH3

CH3

OH CH3

CH3 C CH CH2 C

CH3

Str General B

DIR

IcircNVĂȚĂM

C

CH3

CH3 C CH

OH CH2

CH3

O

C

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

himice şi condițiile acestora Se poate porni

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphellip

(A)

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

B) (C)

(F)

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

tanonă

utanoic

2Cr2O7 + 4H2SO4 3

hellip

l mB = 1314 g helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

CH3

CH2

CHCH

OH

CH3 CH

CH3

CH3 C CH

OH CH2

CH3

O

C

C

CH3

CH2OH

CHC

CH3

O

H CH2CH3 CH2

3 CH2CH3

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O

CH3CCH3

H3

helliphelliphelliphelliphelliphelliphelliphellip 7 puncte

de la 2ndashmetilndash2ndashpentenă prin

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 3 p

(B)

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

helliphelliphelliphelliphelliphelliphellip 30 puncte

helliphelliphelliphelliphelliphelliphelliphellip 15 puncte

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 8 p

(D)

(Frsquo)

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p

+ K2SO4 + Cr2(SO4)3 + 7 H2O

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

helliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphellip 5 puncte

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 5 p

C

CH3

CH2OH

CHCCH3

CH3 O

O-Na+

O

H

C CH2

OH CH3

C

+ CHO

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C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

a Formula moleculară C3H8O3 For

b Modelarea ecuaţiilor reacţiilor ch

c VC3H6(1 atm 27degC) = 30769 m3 helliphellip

NOTĂ Orice altă variantă corect

Barem elaborat de Ignat Iuliana pr

Str General B

DIR

IcircNVĂȚĂM

CH2

CH

CH2

OH

OH

OH

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

mula structurală helliphelliphelliphelliphelliphelliphellip

imice şi condițiile acestora de obţinere a polialco

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

ă de rezolvare se va lua icircn considerare

fesor la Liceul Pedagogic bdquoDP Perpessiciusrdquo

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helliphelliphelliphelliphelliphelliphelliphellip 10 puncte

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p

olului de la propenă helliphellip 4 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

Br ăila

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CH3MgBr (exces) H2O

HO ndash

K2Cr2O7 H+

HCl

C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

Se consideră produsul carbonilicpropionică (A) și acetona (B)

Se cerea Să se indice o schemă de reacțisimultan ambele substanțe (A) și (Bb Să se indice o schemă de reacțiiuna icircn alta

Subiectul IV helliphelliphelliphelliphelliphelliphelliphellip

A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

Substanța (A) are formula moleculcristalizat cu 24 dinitrofenilhidrazide la substanţa (A) se pot scrie ecua

A B D E + NaCl

acetonă + butanal F

F E + H2O

Compusul (B) are formula molec(DNFH) Compusul (E) colorează icirca Scrieți ecuațiile reacțiilor din schb Denumiți conform IUPAC substa

c La dozarea unei soluții a substandin proba de analizat

B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

La echilibrul unei reacţii chimiceCH3COOH 13 moli C2H5OH 23respectivă este 4 Să se calculezeechilibru se mai adaugă 1 mol C2H5

C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

Prin tratarea unui polialcool saturatreprezintă 13695 comparativ cu p

Se cerea Formula moleculară şi structurală b Scrierea ecuaţiilor reacţiilor chiraport cu aerul este 145c Volumul hidrocarburii măsurat lglobal al reacţiilor este 80

Se dau- Mase atomice H - 1 C - 12 N -- Volumul molar V = 224 Lmol- Masa moleculară a aerului microaer =- Constanta universală a gazelor

NOTĂ Timp de lucru 3 ore

Subiecte propuse de Ignat Iuliana

Str General B

DIR

IcircNVĂȚĂM

K2Cr2O7 H+ I2 NaOH

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

u formula moleculară C3H6O sub forma celo

i și condițiile acestora prin care pornind de la

și condițiile lor prin care cele două substanțe (A

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

ră C6H10O2 este neutră față de indicatorii acido a (DNFH) reacționează cu reactiv Tollens și d

iile reacțiilor chimice conform schemei de mai j

C D + CHI3

+ Frsquo

lară C8H18O2 reacționează rapid cu reactivroșu soluția de metilorange și reacționează rapi

mă și cele ale substanței (A) cu DNFH și (A) cunțele notate cu (A) (B) (C) şi (E)

ei (B) se consumă 15mL soluție K2Cr2O7 02M

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

icircntre etanol şi acid acetic compoziţia amestecmoli CH3COOC2H5 şi 23 moli H2O Constan

conversia totală de transformare a acidului acH la volum constant

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

cu anhidridă acidă icircn exces masa moleculară olialcoolul

a polialcooluluiice de obţinere a polialcoolului pornind de la hi

a 1 atm şi 27degC necesar obţinerii a 920 kg po

14 O - 16 Na - 23 S - 32 Cl - 355 K - 39 Cr

2896 gmol= 0082 atmmiddotdm3 molmiddotK

rofesor la Liceul Pedagogic bdquoDP Perpessicius

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helliphelliphelliphelliphelliphelliphelliphellip 7 puncte

r doi izomeri ai săi aldehida

un compus unic să se obțină

) și (B) să se poată transforma

helliphelliphelliphelliphelliphelliphellip 30 puncte

helliphelliphelliphelliphelliphelliphelliphellip 15 puncte

- bazici formează un compusreacția iodoformului Pornind

os

ucas dar nu reacționează cucu reactiv Lucas

reactiv Tollens

Calculați masa substanței (B)

helliphelliphelliphelliphelliphelliphelliphellip 5 puncte

lui este următoarea 13 molita de echilibru la temperaturaetic dacă peste amestecul de

helliphelliphelliphelliphelliphelliphelliphellip 10 puncte

reşte cu 126 Această creştere

drocarbura a cărei densitate icircn

lialcool ştiind că randamentul

- 52 Mn - 55 Br - 80 I - 127

Br ăila

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ndash H2O

230degC

+ 2HA

+ndash

C

O-

COO-K+

O-K+

OL

BA

Subiectul I helliphelliphelliphelliphelliphelliphelliphelliphellipA helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellipa 4 denumiri conform IUPAC times 1p

b Compusul II prezintă doi diastere

Compusul III prezintă 2 atomi de

2 perechi de

c Explicaţie helliphelliphelliphelliphelliphelliphelliphelliphellip

Asemănarea ndash caracterul ba

Deosebirea ndash Amfetamina (

HCl 5 Tetracaina după acilare

rămacircne solubilă icircn soluţia de HCl 5

B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip1 helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

a mezondash3 4ndashdibromhexan (mezofo

b cisndash2 3ndashbutandiol (mezoformă)

c (plusmn)ndash2 3ndashdimetilhexan (amestec r

d cisndash2ndashbutenă

e (plusmn)transndash1 2ndashciclopentandiol (a

2 Modelarea ecuaţiilor reacţiilor ch

se ca produşi finali de reacţie CH2=

Subiectul II helliphelliphelliphelliphelliphelliphelliphelliphellip

A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

1 a helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

C6H5ndashOH + KOH C6H5ndashO

2

acid pndashhidroxindash 2KA

OH

COO-K+

Str General B

DIR

IcircNVĂȚĂM

+ CO2 H2SO4

ndashKHSO

ROH(H2SO4)

ndashH2O

(CH3)2OSO3 CH3OSO3H

OHO-K+

+

COOR

OH

COOH

OCH3

MPIADA DE CHIMIE ndash etapa jude ţ eană

21 februarie 2015

EM DE EVALUARE ndash CLASA A XI-A

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

oizomeri Z (cis) E (trans) 2 structuri times 1p helliphellip

carbon asimetrici

nantiomeri (eritro plusmn treo plusmn) 4 structuri times 05p

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

zic demonstrat prin scrierea ecuaţiilor reacţiilor c

Benzedrina) după acilare pierde caracterul bazi

avacircnd icircn structura sa grefată şi o grupare amin

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

rmă)

cemic)

estec racemic)

imice degradări Hofmann (metilare urmată de icircn

CH2 şi (CH3)3N helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

oline K+

+ + CO2

benzoic

p = 6 atm 125degC

OH

COO-K+

erthelot nr 28-30 Sector 1 010168 Bucureşti

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wwweduro

ECȚIAGENERALĂ

NT PREUNIVERSITAR

4

helliphelliphelliphelliphelliphelliphellip 20 punctehelliphelliphelliphelliphelliphelliphelliphellip 12 punctehelliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p

himice

şi este insolubilă icircn soluţia de

o terţiară care nu se acilează

helliphelliphelliphelliphelliphelliphelliphellip 8 punctehelliphelliphelliphelliphelliphelliphelliphelliphelliphellip 5 p

călzire cu Ag(OH)) obţinacircndu-

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 3 p

helliphelliphelliphelliphelliphelliphelliphellip 25 puncte

helliphelliphelliphelliphelliphelliphelliphellip 15 puncte

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 7 p

OH

COOH

8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem

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OH

COOH

COOH

OH

NO2

O-O-

b (E) acid pndashmetoxibenzoic helliphellip

parahidroxibenzoat de metil helliphelliphellip

parahidroxibenzoat de nndashheptil hellip

c

punct d

punct de to

Ka

Justificare

d Parabenii au potenţial efect cance

2 a helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

lt

b HOndashC6H4ndashCOOH gt H2CO3 gt HC

B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellipa HCOOH rarr CO + H2O hellip

H2C2O4 rarr CO + CO2 + H2

νamestgaze = 003 moli mgaze

b 5 H2C2O4 + 2 KMnO4 + 3 H2SO4

νKMnO4 = 00004 moli m H2C

Subiectul III helliphelliphelliphelliphelliphelliphelliphellip

A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip1 a 3 ecuaţii chimice times 1p helliphelliphellip

Compoziţia icircn procente molare a a

1579 (monoetanolamina)

b η = 95 c= 60 helliphelliphelliphelliphelliphellip

2 4 ecuaţii chimice times 1p helliphelliphelliphellip

B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

C6H5ndashOH + 3Br2 rarr C6H2Br3ndashOH +

Br2 + 2KI rarr 2KBr + I2 helliphelliphelliphellip

I2 + 2Na2S2O3 rarr Na2S4O6 + 2NaI

νNa2S2O3 = 13middot10

-4

moli helliphelliphelliphelliphellip νI2 = νBr2(exces) = 65middot10-4

moli helliphellip

νBr2 icircn reacţia cu fenolul = 6middot10-4

moli helliphellip

p = 94 helliphelliphelliphelliphelliphelliphelliphelliphelliphellip

Str General B

DIR

IcircNVĂȚĂM

O-

CH3O

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

e topire = 159degC

a = 105middot10-4

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

ire = 213degC

26middot10-4

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

rigen datorită nucleului benzenic helliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

lt

O3macr gt HOndashC6H4ndashCOO

macr helliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

09838 g νHCOOH νH2C2O4 = 43 helliphelliphelliphelliphellip

rarr 10 CO2 + K2SO4 + 2MnSO4 + 8 H2Ohelliphelliphellip

2O4middot2H2O = 0126 g p = 96923 helliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

estecului final 6316 (dietanolamina) 2105 (trietanolami

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

3 HBr helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

erthelot nr 28-30 Sector 1 010168 Bucureşti

Tel +40 (0)21 40 63 00

wwweduro

ECȚIAGENERALĂ

NT PREUNIVERSITAR

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphellip 05 p

helliphelliphelliphelliphelliphelliphelliphelliphellip 05 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p helliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphellip 10 punctehelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p

helliphelliphelliphelliphelliphelliphellip 25 puncte

helliphelliphelliphelliphelliphelliphelliphellip 10 punctehelliphelliphelliphelliphelliphelliphelliphelliphelliphellip 3 p

a) helliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p

helliphelliphelliphelliphelliphelliphelliphellip 8 puncte

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 phelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

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CH3

CH2

CH

OH

CHCCH3

CH3

OH

CH3

C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

a Modelarea ecuaţiilor reacţiilor

ozonizare urmată de hidroliză helliphellip

b Ararr helliprarr B helliphelliphelliphelliphellip

Brarr helliprarr A helliphelliphelliphelliphellip

Subiectul IV helliphelliphelliphelliphelliphelliphelliphellip

A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

a 8 ecuaţii chimice times 1p helliphelliphelliphellip

(A) (

(E)

b 4 denumiri conform IUPAC times 1p

(A) 2ndashetilndash3ndashoxondashbutanal

(B) 3ndashetilndash2 metilndash2 4ndashpentandiol

(C) 3ndashetilndash4 metilndash4ndashhidroxindash2ndashpe

(E) acid 2ndashetilndash3ndashmetilndash3ndashhidroxib

c

3 + K

νK2Cr2O7 = 0003 moli νB= 0009 mo

B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

Ctotal = 1

3

∙100

Ctotal = 8447 helliphelliphelliphelliphelliphelliphelliphellip

CH3 C CH

O

CHO

CH2

CH3

OH

CCH3

CH

C

O

CH3

CH2OH

CHCCH3

CH3

OH CH3

CH3 C CH CH2 C

CH3

Str General B

DIR

IcircNVĂȚĂM

C

CH3

CH3 C CH

OH CH2

CH3

O

C

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

himice şi condițiile acestora Se poate porni

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphellip

(A)

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

B) (C)

(F)

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

tanonă

utanoic

2Cr2O7 + 4H2SO4 3

hellip

l mB = 1314 g helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

CH3

CH2

CHCH

OH

CH3 CH

CH3

CH3 C CH

OH CH2

CH3

O

C

C

CH3

CH2OH

CHC

CH3

O

H CH2CH3 CH2

3 CH2CH3

erthelot nr 28-30 Sector 1 010168 Bucureşti

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ECȚIAGENERALĂ

NT PREUNIVERSITAR

O

CH3CCH3

H3

helliphelliphelliphelliphelliphelliphelliphellip 7 puncte

de la 2ndashmetilndash2ndashpentenă prin

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 3 p

(B)

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

helliphelliphelliphelliphelliphelliphellip 30 puncte

helliphelliphelliphelliphelliphelliphelliphellip 15 puncte

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 8 p

(D)

(Frsquo)

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p

+ K2SO4 + Cr2(SO4)3 + 7 H2O

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

helliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphellip 5 puncte

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 5 p

C

CH3

CH2OH

CHCCH3

CH3 O

O-Na+

O

H

C CH2

OH CH3

C

+ CHO

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C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

a Formula moleculară C3H8O3 For

b Modelarea ecuaţiilor reacţiilor ch

c VC3H6(1 atm 27degC) = 30769 m3 helliphellip

NOTĂ Orice altă variantă corect

Barem elaborat de Ignat Iuliana pr

Str General B

DIR

IcircNVĂȚĂM

CH2

CH

CH2

OH

OH

OH

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

mula structurală helliphelliphelliphelliphelliphelliphellip

imice şi condițiile acestora de obţinere a polialco

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

ă de rezolvare se va lua icircn considerare

fesor la Liceul Pedagogic bdquoDP Perpessiciusrdquo

erthelot nr 28-30 Sector 1 010168 Bucureşti

Tel +40 (0)21 40 63 00

wwweduro

ECȚIAGENERALĂ

NT PREUNIVERSITAR

helliphelliphelliphelliphelliphelliphelliphellip 10 puncte

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p

olului de la propenă helliphellip 4 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

Br ăila

Page 4: 2015 Chimie Judeteana Clasa a Xia Subiectebarem

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ndash H2O

230degC

+ 2HA

+ndash

C

O-

COO-K+

O-K+

OL

BA

Subiectul I helliphelliphelliphelliphelliphelliphelliphelliphellipA helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellipa 4 denumiri conform IUPAC times 1p

b Compusul II prezintă doi diastere

Compusul III prezintă 2 atomi de

2 perechi de

c Explicaţie helliphelliphelliphelliphelliphelliphelliphelliphellip

Asemănarea ndash caracterul ba

Deosebirea ndash Amfetamina (

HCl 5 Tetracaina după acilare

rămacircne solubilă icircn soluţia de HCl 5

B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip1 helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

a mezondash3 4ndashdibromhexan (mezofo

b cisndash2 3ndashbutandiol (mezoformă)

c (plusmn)ndash2 3ndashdimetilhexan (amestec r

d cisndash2ndashbutenă

e (plusmn)transndash1 2ndashciclopentandiol (a

2 Modelarea ecuaţiilor reacţiilor ch

se ca produşi finali de reacţie CH2=

Subiectul II helliphelliphelliphelliphelliphelliphelliphelliphellip

A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

1 a helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

C6H5ndashOH + KOH C6H5ndashO

2

acid pndashhidroxindash 2KA

OH

COO-K+

Str General B

DIR

IcircNVĂȚĂM

+ CO2 H2SO4

ndashKHSO

ROH(H2SO4)

ndashH2O

(CH3)2OSO3 CH3OSO3H

OHO-K+

+

COOR

OH

COOH

OCH3

MPIADA DE CHIMIE ndash etapa jude ţ eană

21 februarie 2015

EM DE EVALUARE ndash CLASA A XI-A

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

oizomeri Z (cis) E (trans) 2 structuri times 1p helliphellip

carbon asimetrici

nantiomeri (eritro plusmn treo plusmn) 4 structuri times 05p

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

zic demonstrat prin scrierea ecuaţiilor reacţiilor c

Benzedrina) după acilare pierde caracterul bazi

avacircnd icircn structura sa grefată şi o grupare amin

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

rmă)

cemic)

estec racemic)

imice degradări Hofmann (metilare urmată de icircn

CH2 şi (CH3)3N helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

oline K+

+ + CO2

benzoic

p = 6 atm 125degC

OH

COO-K+

erthelot nr 28-30 Sector 1 010168 Bucureşti

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ECȚIAGENERALĂ

NT PREUNIVERSITAR

4

helliphelliphelliphelliphelliphelliphellip 20 punctehelliphelliphelliphelliphelliphelliphelliphellip 12 punctehelliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p

himice

şi este insolubilă icircn soluţia de

o terţiară care nu se acilează

helliphelliphelliphelliphelliphelliphelliphellip 8 punctehelliphelliphelliphelliphelliphelliphelliphelliphelliphellip 5 p

călzire cu Ag(OH)) obţinacircndu-

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 3 p

helliphelliphelliphelliphelliphelliphelliphellip 25 puncte

helliphelliphelliphelliphelliphelliphelliphellip 15 puncte

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 7 p

OH

COOH

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OH

COOH

COOH

OH

NO2

O-O-

b (E) acid pndashmetoxibenzoic helliphellip

parahidroxibenzoat de metil helliphelliphellip

parahidroxibenzoat de nndashheptil hellip

c

punct d

punct de to

Ka

Justificare

d Parabenii au potenţial efect cance

2 a helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

lt

b HOndashC6H4ndashCOOH gt H2CO3 gt HC

B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellipa HCOOH rarr CO + H2O hellip

H2C2O4 rarr CO + CO2 + H2

νamestgaze = 003 moli mgaze

b 5 H2C2O4 + 2 KMnO4 + 3 H2SO4

νKMnO4 = 00004 moli m H2C

Subiectul III helliphelliphelliphelliphelliphelliphelliphellip

A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip1 a 3 ecuaţii chimice times 1p helliphelliphellip

Compoziţia icircn procente molare a a

1579 (monoetanolamina)

b η = 95 c= 60 helliphelliphelliphelliphelliphellip

2 4 ecuaţii chimice times 1p helliphelliphelliphellip

B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

C6H5ndashOH + 3Br2 rarr C6H2Br3ndashOH +

Br2 + 2KI rarr 2KBr + I2 helliphelliphelliphellip

I2 + 2Na2S2O3 rarr Na2S4O6 + 2NaI

νNa2S2O3 = 13middot10

-4

moli helliphelliphelliphelliphellip νI2 = νBr2(exces) = 65middot10-4

moli helliphellip

νBr2 icircn reacţia cu fenolul = 6middot10-4

moli helliphellip

p = 94 helliphelliphelliphelliphelliphelliphelliphelliphelliphellip

Str General B

DIR

IcircNVĂȚĂM

O-

CH3O

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

e topire = 159degC

a = 105middot10-4

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

ire = 213degC

26middot10-4

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

rigen datorită nucleului benzenic helliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

lt

O3macr gt HOndashC6H4ndashCOO

macr helliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

09838 g νHCOOH νH2C2O4 = 43 helliphelliphelliphelliphellip

rarr 10 CO2 + K2SO4 + 2MnSO4 + 8 H2Ohelliphelliphellip

2O4middot2H2O = 0126 g p = 96923 helliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

estecului final 6316 (dietanolamina) 2105 (trietanolami

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

3 HBr helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

erthelot nr 28-30 Sector 1 010168 Bucureşti

Tel +40 (0)21 40 63 00

wwweduro

ECȚIAGENERALĂ

NT PREUNIVERSITAR

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphellip 05 p

helliphelliphelliphelliphelliphelliphelliphelliphellip 05 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p helliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphellip 10 punctehelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p

helliphelliphelliphelliphelliphelliphellip 25 puncte

helliphelliphelliphelliphelliphelliphelliphellip 10 punctehelliphelliphelliphelliphelliphelliphelliphelliphelliphellip 3 p

a) helliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p

helliphelliphelliphelliphelliphelliphelliphellip 8 puncte

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 phelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem

httpslidepdfcomreaderfull2015-chimie-judeteana-clasa-a-xia-subiectebarem 67

CH3

CH2

CH

OH

CHCCH3

CH3

OH

CH3

C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

a Modelarea ecuaţiilor reacţiilor

ozonizare urmată de hidroliză helliphellip

b Ararr helliprarr B helliphelliphelliphelliphellip

Brarr helliprarr A helliphelliphelliphelliphellip

Subiectul IV helliphelliphelliphelliphelliphelliphelliphellip

A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

a 8 ecuaţii chimice times 1p helliphelliphelliphellip

(A) (

(E)

b 4 denumiri conform IUPAC times 1p

(A) 2ndashetilndash3ndashoxondashbutanal

(B) 3ndashetilndash2 metilndash2 4ndashpentandiol

(C) 3ndashetilndash4 metilndash4ndashhidroxindash2ndashpe

(E) acid 2ndashetilndash3ndashmetilndash3ndashhidroxib

c

3 + K

νK2Cr2O7 = 0003 moli νB= 0009 mo

B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

Ctotal = 1

3

∙100

Ctotal = 8447 helliphelliphelliphelliphelliphelliphelliphellip

CH3 C CH

O

CHO

CH2

CH3

OH

CCH3

CH

C

O

CH3

CH2OH

CHCCH3

CH3

OH CH3

CH3 C CH CH2 C

CH3

Str General B

DIR

IcircNVĂȚĂM

C

CH3

CH3 C CH

OH CH2

CH3

O

C

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

himice şi condițiile acestora Se poate porni

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphellip

(A)

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

B) (C)

(F)

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

tanonă

utanoic

2Cr2O7 + 4H2SO4 3

hellip

l mB = 1314 g helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

CH3

CH2

CHCH

OH

CH3 CH

CH3

CH3 C CH

OH CH2

CH3

O

C

C

CH3

CH2OH

CHC

CH3

O

H CH2CH3 CH2

3 CH2CH3

erthelot nr 28-30 Sector 1 010168 Bucureşti

Tel +40 (0)21 40 63 00

wwweduro

ECȚIAGENERALĂ

NT PREUNIVERSITAR

O

CH3CCH3

H3

helliphelliphelliphelliphelliphelliphelliphellip 7 puncte

de la 2ndashmetilndash2ndashpentenă prin

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 3 p

(B)

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

helliphelliphelliphelliphelliphelliphellip 30 puncte

helliphelliphelliphelliphelliphelliphelliphellip 15 puncte

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 8 p

(D)

(Frsquo)

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p

+ K2SO4 + Cr2(SO4)3 + 7 H2O

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

helliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphellip 5 puncte

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 5 p

C

CH3

CH2OH

CHCCH3

CH3 O

O-Na+

O

H

C CH2

OH CH3

C

+ CHO

8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem

httpslidepdfcomreaderfull2015-chimie-judeteana-clasa-a-xia-subiectebarem 77

C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

a Formula moleculară C3H8O3 For

b Modelarea ecuaţiilor reacţiilor ch

c VC3H6(1 atm 27degC) = 30769 m3 helliphellip

NOTĂ Orice altă variantă corect

Barem elaborat de Ignat Iuliana pr

Str General B

DIR

IcircNVĂȚĂM

CH2

CH

CH2

OH

OH

OH

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

mula structurală helliphelliphelliphelliphelliphelliphellip

imice şi condițiile acestora de obţinere a polialco

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

ă de rezolvare se va lua icircn considerare

fesor la Liceul Pedagogic bdquoDP Perpessiciusrdquo

erthelot nr 28-30 Sector 1 010168 Bucureşti

Tel +40 (0)21 40 63 00

wwweduro

ECȚIAGENERALĂ

NT PREUNIVERSITAR

helliphelliphelliphelliphelliphelliphelliphellip 10 puncte

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p

olului de la propenă helliphellip 4 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

Br ăila

Page 5: 2015 Chimie Judeteana Clasa a Xia Subiectebarem

8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem

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OH

COOH

COOH

OH

NO2

O-O-

b (E) acid pndashmetoxibenzoic helliphellip

parahidroxibenzoat de metil helliphelliphellip

parahidroxibenzoat de nndashheptil hellip

c

punct d

punct de to

Ka

Justificare

d Parabenii au potenţial efect cance

2 a helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

lt

b HOndashC6H4ndashCOOH gt H2CO3 gt HC

B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellipa HCOOH rarr CO + H2O hellip

H2C2O4 rarr CO + CO2 + H2

νamestgaze = 003 moli mgaze

b 5 H2C2O4 + 2 KMnO4 + 3 H2SO4

νKMnO4 = 00004 moli m H2C

Subiectul III helliphelliphelliphelliphelliphelliphelliphellip

A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip1 a 3 ecuaţii chimice times 1p helliphelliphellip

Compoziţia icircn procente molare a a

1579 (monoetanolamina)

b η = 95 c= 60 helliphelliphelliphelliphelliphellip

2 4 ecuaţii chimice times 1p helliphelliphelliphellip

B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

C6H5ndashOH + 3Br2 rarr C6H2Br3ndashOH +

Br2 + 2KI rarr 2KBr + I2 helliphelliphelliphellip

I2 + 2Na2S2O3 rarr Na2S4O6 + 2NaI

νNa2S2O3 = 13middot10

-4

moli helliphelliphelliphelliphellip νI2 = νBr2(exces) = 65middot10-4

moli helliphellip

νBr2 icircn reacţia cu fenolul = 6middot10-4

moli helliphellip

p = 94 helliphelliphelliphelliphelliphelliphelliphelliphelliphellip

Str General B

DIR

IcircNVĂȚĂM

O-

CH3O

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

e topire = 159degC

a = 105middot10-4

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

ire = 213degC

26middot10-4

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

rigen datorită nucleului benzenic helliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

lt

O3macr gt HOndashC6H4ndashCOO

macr helliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

09838 g νHCOOH νH2C2O4 = 43 helliphelliphelliphelliphellip

rarr 10 CO2 + K2SO4 + 2MnSO4 + 8 H2Ohelliphelliphellip

2O4middot2H2O = 0126 g p = 96923 helliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

estecului final 6316 (dietanolamina) 2105 (trietanolami

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

3 HBr helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

erthelot nr 28-30 Sector 1 010168 Bucureşti

Tel +40 (0)21 40 63 00

wwweduro

ECȚIAGENERALĂ

NT PREUNIVERSITAR

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphellip 05 p

helliphelliphelliphelliphelliphelliphelliphelliphellip 05 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p helliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphellip 10 punctehelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p

helliphelliphelliphelliphelliphelliphellip 25 puncte

helliphelliphelliphelliphelliphelliphelliphellip 10 punctehelliphelliphelliphelliphelliphelliphelliphelliphelliphellip 3 p

a) helliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p

helliphelliphelliphelliphelliphelliphelliphellip 8 puncte

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 phelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem

httpslidepdfcomreaderfull2015-chimie-judeteana-clasa-a-xia-subiectebarem 67

CH3

CH2

CH

OH

CHCCH3

CH3

OH

CH3

C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

a Modelarea ecuaţiilor reacţiilor

ozonizare urmată de hidroliză helliphellip

b Ararr helliprarr B helliphelliphelliphelliphellip

Brarr helliprarr A helliphelliphelliphelliphellip

Subiectul IV helliphelliphelliphelliphelliphelliphelliphellip

A helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

a 8 ecuaţii chimice times 1p helliphelliphelliphellip

(A) (

(E)

b 4 denumiri conform IUPAC times 1p

(A) 2ndashetilndash3ndashoxondashbutanal

(B) 3ndashetilndash2 metilndash2 4ndashpentandiol

(C) 3ndashetilndash4 metilndash4ndashhidroxindash2ndashpe

(E) acid 2ndashetilndash3ndashmetilndash3ndashhidroxib

c

3 + K

νK2Cr2O7 = 0003 moli νB= 0009 mo

B helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

Ctotal = 1

3

∙100

Ctotal = 8447 helliphelliphelliphelliphelliphelliphelliphellip

CH3 C CH

O

CHO

CH2

CH3

OH

CCH3

CH

C

O

CH3

CH2OH

CHCCH3

CH3

OH CH3

CH3 C CH CH2 C

CH3

Str General B

DIR

IcircNVĂȚĂM

C

CH3

CH3 C CH

OH CH2

CH3

O

C

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

himice şi condițiile acestora Se poate porni

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphellip

(A)

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

B) (C)

(F)

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

tanonă

utanoic

2Cr2O7 + 4H2SO4 3

hellip

l mB = 1314 g helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

CH3

CH2

CHCH

OH

CH3 CH

CH3

CH3 C CH

OH CH2

CH3

O

C

C

CH3

CH2OH

CHC

CH3

O

H CH2CH3 CH2

3 CH2CH3

erthelot nr 28-30 Sector 1 010168 Bucureşti

Tel +40 (0)21 40 63 00

wwweduro

ECȚIAGENERALĂ

NT PREUNIVERSITAR

O

CH3CCH3

H3

helliphelliphelliphelliphelliphelliphelliphellip 7 puncte

de la 2ndashmetilndash2ndashpentenă prin

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 3 p

(B)

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

helliphelliphelliphelliphelliphelliphellip 30 puncte

helliphelliphelliphelliphelliphelliphelliphellip 15 puncte

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 8 p

(D)

(Frsquo)

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p

+ K2SO4 + Cr2(SO4)3 + 7 H2O

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

helliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

helliphelliphelliphelliphelliphelliphelliphellip 5 puncte

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 5 p

C

CH3

CH2OH

CHCCH3

CH3 O

O-Na+

O

H

C CH2

OH CH3

C

+ CHO

8192019 2015 Chimie Judeteana Clasa a Xia Subiectebarem

httpslidepdfcomreaderfull2015-chimie-judeteana-clasa-a-xia-subiectebarem 77

C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

a Formula moleculară C3H8O3 For

b Modelarea ecuaţiilor reacţiilor ch

c VC3H6(1 atm 27degC) = 30769 m3 helliphellip

NOTĂ Orice altă variantă corect

Barem elaborat de Ignat Iuliana pr

Str General B

DIR

IcircNVĂȚĂM

CH2

CH

CH2

OH

OH

OH

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

mula structurală helliphelliphelliphelliphelliphelliphellip

imice şi condițiile acestora de obţinere a polialco

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

ă de rezolvare se va lua icircn considerare

fesor la Liceul Pedagogic bdquoDP Perpessiciusrdquo

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helliphelliphelliphelliphelliphelliphelliphellip 10 puncte

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p

olului de la propenă helliphellip 4 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

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O

CH3CCH3

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de la 2ndashmetilndash2ndashpentenă prin

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(B)

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helliphelliphelliphelliphelliphelliphelliphellip 15 puncte

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helliphelliphelliphelliphelliphelliphelliphelliphellip 1 p

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C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

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mula structurală helliphelliphelliphelliphelliphelliphellip

imice şi condițiile acestora de obţinere a polialco

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

ă de rezolvare se va lua icircn considerare

fesor la Liceul Pedagogic bdquoDP Perpessiciusrdquo

erthelot nr 28-30 Sector 1 010168 Bucureşti

Tel +40 (0)21 40 63 00

wwweduro

ECȚIAGENERALĂ

NT PREUNIVERSITAR

helliphelliphelliphelliphelliphelliphelliphellip 10 puncte

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p

olului de la propenă helliphellip 4 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

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C helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

a Formula moleculară C3H8O3 For

b Modelarea ecuaţiilor reacţiilor ch

c VC3H6(1 atm 27degC) = 30769 m3 helliphellip

NOTĂ Orice altă variantă corect

Barem elaborat de Ignat Iuliana pr

Str General B

DIR

IcircNVĂȚĂM

CH2

CH

CH2

OH

OH

OH

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

mula structurală helliphelliphelliphelliphelliphelliphellip

imice şi condițiile acestora de obţinere a polialco

helliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphelliphellip

ă de rezolvare se va lua icircn considerare

fesor la Liceul Pedagogic bdquoDP Perpessiciusrdquo

erthelot nr 28-30 Sector 1 010168 Bucureşti

Tel +40 (0)21 40 63 00

wwweduro

ECȚIAGENERALĂ

NT PREUNIVERSITAR

helliphelliphelliphelliphelliphelliphelliphellip 10 puncte

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 4 p

olului de la propenă helliphellip 4 p

helliphelliphelliphelliphelliphelliphelliphelliphelliphellip 2 p

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