Referat la fizică

Sistemul termic cu numărul 9.

Elevi : Alecu Mihnea

Costea Alexandru

Georgescu Alexandru

η=f (ε , γ ) ε=V 3V 1

γ=C p

C v

Q1

1 2

Q = 0

T1=ct

Q2

3

η = 1 - |Q2|Q1

Q1 = ν Cp (T2-T1)

|Q2|=ν RT1 lnV 3V 1

η = 1 - RT 1 ln

V 3V 1

C p ¿¿

Din γ = CpC v

⟹Cp = γCp - γCv

Cp – R ; Cp=γRγ−1

η = 1 - RT1 ln

V 3V 1

γ Rγ−1

(T 2−T 1) =

(γ−1)T1 lnV 3V 1

γ (T 2−T 1) =

(γ−1 ) lnV 3V 1

γ (T 2T 1

−1)

V 1T 1

= V 2T 2

⟹ T2T1

=V 2V 1

p1V2γ

= p3V3γ

(*) V2γV3= V3

γ⟹ V2=V3γ√V 1V 3 =V3

1εγ

⟹

p3V3= p1V1

⟹ T2T1 =

V 31ε γ

V 1 = ε

ε1γ = ε

1−1γ

η = 1 - ( γ−1 ) lnε

γ (ϵ1−1γ−1)